Concept explainers
(a)
(a)
Answer to Problem 90E
Probability for two or fewer students would win a prize is 0.1028.
Explanation of Solution
Given information:
Number of trials,
Probability of success,
Calculations:
According to the binomial probability,
At
The binomial probability to be evaluated as:
At
The binomial probability to be evaluated as:
At
The binomial probability to be evaluated as:
Since two different numbers of successes are impossible on same simulation.
Apply addition rule for mutually exclusive events:
Thus,
If company’s claim is true, probability for two or fewer students would win a prize is 0.1028.
(b)
Whether the result of two cap winners in Grayson’s class gives convincing evidence that the company’s 1 − in − 6 claim is false.
(b)
Answer to Problem 90E
No convincing evidence exists for company’s 1 − in − 6 claim is false.
Explanation of Solution
Given information:
Number of trials,
Probability of success,
The probability less than 0.05 is considered to be small.
Note that
From Part (a),
The probability of at most 2 winners is 0.1028, which is very much larger than 0.05.
This indicates
It is likely to obtain two winners.
Thus,
There is no convincing evidence that the company’s 1 − in − 6 claim is false.
Chapter 6 Solutions
PRACTICE OF STATISTICS F/AP EXAM
Additional Math Textbook Solutions
An Introduction to Mathematical Statistics and Its Applications (6th Edition)
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Elementary Statistics (13th Edition)
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