Chapter 6.1, Problem 2E

(a)

To determine

To Calculate: the event in terms of Y and its probability.

Answer to Problem 2E

Y=1;

P(Y=1) =0.2

Explanation of Solution

Formula used:

  ${\displaystyle \sum \text{P}\left(Y\right)=1}$

Calculation:

  $Y=1;$

  $\begin{array}{c}\because {\displaystyle \sum \text{P}\left(Y\right)=1}\\ \text{P}\left(Y=1\right)=1-\left\{\text{P}\left(0\right)+\text{P}\left(2\right)+\text{P}\left(3\right)+\text{P}\left(4\right)\right\}\\ =1-\left\{0.1+0.3+0.3+0.1\right\}\\ =1-0.8\\ =0.2\end{array}$

(b)

To determine

To Calculate: the probability for at least 2 nonword errors

Answer to Problem 2E

  $\text{P}\left(Y\ge 2\right)=0.7$

Explanation of Solution

Calculation:

  $\begin{array}{c}\text{P}\left(Y\ge 2\right)=\text{P}\left(2\right)+\text{P}\left(3\right)+\text{P}\left(4\right)\\ =0.3+0.3+.1\\ =0.7\end{array}$