The number of moles required to produce 15 mol of C 6 H 12 O 6 glucose. Concept introduction: Mole: A mole is corresponds to the mass of a substance that contains 6 .023×10 23 particles of the substance. The mole is the SI units for the amount of a substance and its symbol is mol. 1 mole of carbon -12 has a mass of 12 gram and it contains 6 .022140857 x 10 23 of carbon atoms The Mole and Avogadro’s number •For convenience in considering reactions and calculating quantities, chemists think in terms of moles of substances. •A mole is a quantity of particles defined as Avogadro’s number of particles or formula units of elements or compounds. •The molecular or formula weight of a compound is the sum of the mass of all atoms in the formula. •A mole also happens to be 22.4 L of an ideal gas under standard conditions, so 22.4 L of ideal gas represent one gram formula weight of the compound.

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Chapter 6.3, Problem 6.9P

Interpretation Introduction

Interpretation:

The number of moles required to produce 15 mol of C6H12O6 glucose.

Concept introduction:

Mole:

A mole is corresponds to the mass of a substance that contains 6.023×1023 particles of the substance.

The mole is the SI units for the amount of a substance and its symbol is mol.

1 mole of carbon -12 has a mass of 12 gram and it contains

6.022140857 x 1023 of carbon atoms

The Mole and Avogadro’s number

•For convenience in considering reactions and calculating quantities, chemists think in terms of moles of substances.

•A mole is a quantity of particles defined as Avogadro’s number of particles or formula units of elements or compounds.

•The molecular or formula weight of a compound is the sum of the mass of all atoms in the formula.

•A mole also happens to be 22.4 L of an ideal gas under standard conditions, so 22.4 L of ideal gas represent one gram formula weight of the compound.

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