Chapter 6.2, Problem 49STP

To determine

The positive difference between the median and mean of given data.

Answer to Problem 49STP

Option B. is correct.

Explanation of Solution

Given:

The given data is:

Calculation:

The mean will be:

  $\begin{array}{l}Mean=\frac{193+180+154+147+135+130}{6}\\ Mean=\frac{939}{6}\\ Mean=156.5\\ Mean\approx 157\end{array}$

Arrange the data in increasing order;

  $130,135,147,154,180,193$

The middle value will be third and fourth values.

Finding median:

  $\begin{array}{l}Median=\frac{147+154}{2}\\ Median=\frac{301}{2}\\ Median=150.5\\ Median\approx 151\end{array}$

The positive difference between the mean and median is 157 − 151 = 6.

Therefore, Option B. is correct.