INTREPRETATION: The reason behind for formation of identical amounts of enantiomers formed reaction between cis-2-heptene and B r 2 should be determined. CONCEPT INTRODUCTION: Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation. Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom. Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation. Chemical reaction involves bond making and breaking of two or more reactants in order to attain products from the reactants. The curved arrows are generally used to indicate the flow of electrons present in the reaction. Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction. In addition reaction of alkenes when two substituents are placed on same side of C = C then it is named as s y n addition if it is placed on opposite sides of C = C it is defined as anti-addition. Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms. Oxidizing Reagents: The chemical agents used to add oxygen or remove hydrogen which finally reduced on oxidizing the other compound. Carbocation: it is carbon ion that bears a positive charge on it. Carbocation stability order:

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Chapter 6.13, Problem 46P

Interpretation Introduction

INTREPRETATION:

The reason behind for formation of identical amounts of enantiomers formed reaction between cis-2-heptene and Br2 should be determined.

CONCEPT INTRODUCTION:

Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.

Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.

Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.

Chemical reaction involves bond making and breaking of two or more reactants in order to attain products from the reactants.

The curved arrows are generally used to indicate the flow of electrons present in the reaction.

Addition Reaction: It is defined as chemical reaction in which two given molecules combines and forms product. The types of addition reactions are electrophilic addition, nucleophilic addition, free radical additions and cycloadditions. Generally, compounds with carbon-hetero atom bonds favors addition reaction.

In addition reaction of alkenes when two substituents are placed on same side of C=C then it is named as syn addition if it is placed on opposite sides of C=C it is defined as anti-addition.

Oxidation Reaction: It involves loss of electrons, addition of oxygen atoms or removal of hydrogen atoms.

Oxidizing Reagents: The chemical agents used to add oxygen or remove hydrogen which finally reduced on oxidizing the other compound.

Carbocation: it is carbon ion that bears a positive charge on it.

Carbocation stability order:

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Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br‍(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.

е. Д CH3 D*, D20

C. NaOMe, Br Br