Explanation The truss is loaded as shown in the figure. The free body diagram for the entire truss is given by Figure 1. The sum of the moments in the counter clockwise direction about A for the entire truss is given as, H ( 36 ft ) − ( 4 kips ) ( 9 ft ) − ( 4 kips ) ( 18 ft ) = 0 (I) Solve for H from (I). H ( 36 ft ) − ( 4 kips ) ( 9 ft ) − ( 4 kips ) ( 18 ft ) = 0 H = 3.00 kips The sum of the forces in the positive x direction for the entire truss is given as, A x = 0 (II) The sum of the forces in the positive y direction for the entire truss is given as, A y + 3 kips − 8 kips = 0 A y = 5.00 kips (III) The member D E and F G are zero force members. This means that force on the member B D and D F will be the same. So will be the force on the members E G and G H . The free body diagram of the joint A is given as, From the diagram the relation between the force on the members A B and A C are given as, F A B 5 = F A C 3 = A y 4 (IV) The free body diagram of the joint C is given as, From the diagram the sum of the forces in the positive x direction is given as, F C E = 3.75 kips (V) From the diagram the sum of the forces in the positive y direction is given as, F B C = 4.00 kips (VI) The free body diagram of the joint B is given as, From the diagram the sum of the forces in the positive y direction is given as, − 4 5 F B E + 4 5 F A B − F B C = 0 (VII) From the diagram the sum of the forces in the positive x direction is given as, 3 5 F A B + 3 5 F B E + F B D = 0 (VIII) The free body diagram of the joint F is given as, From the diagram, the relation between the force on the members are given as, F E F 5 = F F H 5 = F D F 6 (IX) The free body diagram of the joint F is given as, From the diagram, the relation between the force on the members are given as, F G H 3 = H 4 (X) Conclusion: Solve for F A B from (IV) by substituting 5.00 kips for A y . F A B 5 = 5.00 kips 4 F A B = 6

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Author: BEER

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Chapter 6.1, Problem 6.20P

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The force in each member of the Pratt bridge.

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Chapter 6.1, Problem 6.19P

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Chapter 6 Solutions

VECTOR MECH...,STAT.+DYNA.(LL)-W/ACCESS

Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.3P Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.5P Ch. 6.1 - Using the method of joints, determine the force in...Ch. 6.1 - 6.1 through 6.8 Using the method of joints,...Ch. 6.1 - Prob. 6.8P Ch. 6.1 - 6.9 and 6.10 Determine the force in each member of...Ch. 6.1 - Prob. 6.10P

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The force in each member of the Pratt bridge.

Solution Summary: The author explains the force in each member of the Pratt bridge. The free body diagram for the entire truss is given by Figure 1.

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The force in each member of the Pratt bridge.

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Chapter 6 Solutions