Concept explainers
a.
To estimate: velocity of a projectile after 5 sec.
a.
Answer to Problem 27E
Velocity of a projectile after 5 sec is: 240 ft/sec2.
Explanation of Solution
Given:
Initial velocity is 400 ft/sec.
Formula used:
where v is the final velocity u is the initial velocity g is the gravitational constant and t is the time.
Calculation:
Putting the values in
We get,
Therefore, the velocity of a projectile after 5 sec is: 240 ft/sec2.
b
To estimate: the lower estimate of height attained after 5 seconds using RRAM5.
b
Answer to Problem 27E
Estimated height is: 1520 ft.
Explanation of Solution
Given:
Initial velocity is 400 ft/sec.
Formula used:
The area under the velocity curve gives the height (distance in vertical sense) attained by an object.
RRAM5 refers to Right Rectangle Approximation Method, in which the right points of the each interval are taken as the height of the rectangle to find the area below it and the value of n is 5.
Calculation:
From part (a) the equation for the velocity is given by
As t is given as 5 sec and n = 5,
RRAM5 method gives
Therefore, estimated height is: 1520 ft.
Chapter 6 Solutions
Calculus: Graphical, Numerical, Algebraic
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