Chapter 6, Problem 72AE

a)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  ${\text{Na}}_{\text{2}}\text{O}\left(s\right)+\frac{1}{2}{\text{O}}_{\text{2}}\left(g\right)\rightleftharpoons {\text{Na}}_2{\text{O}}_3\left(s\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions become equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .

b)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  $\text{NaO}\left(g\right)+{\text{Na}}_2\text{O}\left(s\right)\rightleftharpoons {\text{Na}}_2{\text{O}}_2\left(s\right)+\text{Na}\left(l\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions become equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .

c)

Interpretation Introduction

Interpretation:Value of equilibrium constant $K$ in below reaction is to be determined.

  $\text{2NaO}\left(s\right)\rightleftharpoons {\text{Na}}_2{\text{O}}_2\left(s\right)$

Concept introduction:Chemical equilibrium is taken into consideration if rate of backward and forward reactions become equal. At this stage, reactants and products have constant concentration. Equilibrium constant is denoted by $K$ .