
Concept explainers
Write a letter to a friend who has not yet studied physics and tell what you've learned about Galileo introducing the concepts of acceleration and inertia. Tell of how Galileo was also familiar with forces, but didn’t see the connection among these three concepts. Tell how Isaac Newton did see the connection, revealed in his second law of motion. Explain with the second law why heavy and light objects in free fall gain the same speed in the same time. In this letter, it’s okay to use an equation or two, making it clear that you see equations as a shorthand notation of explanations.

To Explain: The connection between the Force, acceleration and inertia, Newton’s second law and the way heavy and light objects gain same speed in free falls.
Explanation of Solution
Introduction:
Inertia is the property or can say tendency of a body to be in the rest position unless any force acts on it.More is the mass, more is the inertia to the body.
Acceleration is the rate of change of velocity with respect to time.
Force is the product of mass and acceleration.
Galileowas aware of the concept of inertia, acceleration and force but he couldn’t find out the relationship between these quantities, which were later explained by Newton.
According to Newton’s second law of motion, product of mass and rate of change of velocity is equal to the force acting on the body.
Where,
m is the mass of body
F is the force acting on the body.
Mass of the body is related to inertia.
The above equation gives relationship between Force, acceleration and inertia.
Free fall is the motion of an object when no other forces except for gravity act on it. There is no air resistance offered to the falling object. No speed dissipative forces act on the object. When two objects, one is heavier and another is lighter experience a free fall, then both the objects would reach the ground at the same time, because the gravity acting on both bodies is same. So they would have same acceleration and hence velocity. Hence, both objects will reach the ground at the same time.
Conclusion:
Gravitational pull is always same for all bodies but because of air resistance the lighter object cannot reach the ground early. In case of free fall, there are no dissipative forces. so,the objects will reach the ground at the same time with the same speed.
Chapter 6 Solutions
Conceptual Physics: The High School Physics Program
Additional Science Textbook Solutions
Microbiology with Diseases by Body System (5th Edition)
Biology: Life on Earth with Physiology (11th Edition)
College Physics: A Strategic Approach (3rd Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Organic Chemistry (8th Edition)
Human Physiology: An Integrated Approach (8th Edition)
- No chatgpt pls will upvotearrow_forward2. 1. Tube Rating Charts Name: Directions: For the given information state if the technique is safe or unsafe and why. 60 Hertz Stator Operation Effective Focal Spot Size- 0.6 mm Peak Kilovolts MA 2 150 140 130 120 110 100 90 80 70 2501 60 50 40 30 .01 .02 .04.06 .1 .2 .4.6 1 8 10 Maximum Exposure Time In Seconds Is an exposure of 80 kVp, 0.1 second and 200 mA within the limits of the single phase, 0.6 mm focal spot tube rating chart above? Is an exposure of 100 kVp, 0.9 second and 150 mA within the limits of the single phase, 0.6 mm focal spot tube rating chart above?arrow_forwardQ: You have a CO2 laser resonator (λ = 10.6 μm). It has two curved mirrors with R₁=10m, R2= 8m, and mirror separation /= 5m. Find: R2-10 m tl Z-O 12 R1-8 m 1. Confocal parameter. b= 21w2/2 =√1 (R1-1)(R2-1)(R1+R2-21)/R1+R2-21) 2. Beam waist at t₁ & t2- 3. Waist radius (wo). 4. 5. The radius of the laser beam outside the resonator and about 0.5m from R₂- Divergence angle. 6. Radius of curvature for phase front on the mirrors R₁ & R2-arrow_forward
- No chatgpt pls will upvotearrow_forwardSARET CRKS AUTOWAY 12. A stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff? 13. A ball is dropped from rest at the top of a building that is 320 m tall. Assuming no air resistance, what is the speed of the ball just before it strikes the ground? 14. Estimate (a) how long it took King Kong to fall straight down from the top of the Empire State Building (280m high), and (b) his velocity just before "landing". Useful equations For Constant Velocity: V => D X = V₁t + Xo For Constant Acceleration: Vr = V + at X = Xo+Vot + v=V+2a(X-Xo) \prom = V +V V velocity t = time D Distance X = Final Position Xo Initial Position V = Final Velocity Vo Initial Velocity a = acceleration For free fall Yf = Final Position Yo Initial Position g = 9.80 m $2 For free fall: V = V + gt Y=Yo+Vo t + +gt V,² = V₁²+2g (Y-Yo) V+Vo Vprom= 2 6arrow_forwardSolve the problemsarrow_forward
- A 11 kg weight is attached to a spring with constant k = 99 N/m and subjected to an external force F(t) =-704 sin(5t). The weight is initially displaced 4 meters above equilibrium and given an upward velocity of 5 m/s. Find its displacement for t> 0. y(t) וןarrow_forward7. A race car accelerates from rest to 55 m s-1 in 5.0 seconds. The acceleration of the car Is m s-² 8. An object's speed increases uniformly from 10.5 km per hour to 99.8 km per hour in 2.41 seconds. Calculate the acceleration in m s-2 and express your answer to three significant figures. 9. The acceleration-time graph of a car is shown below. The initial speed of the car is 5.0 m s-1. # Acceleration (ms) 12 8.0- 4.0- 2.0 4.0 6.0 Time (s) Calculate the velocity of the car at t = 4.0 s. 3arrow_forwardNo chatgpt pls will upvotearrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





