The auto in the sketch moves forward as the brakes are applied. A bystander says that during the interval of braking, the auto’s velocity and acceleration are in opposite directions. Do you agree or disagree?
To explain: Whether a person agree or disagree with the fact that auto’s velocity and acceleration are in opposite direction.
Explanation of Solution
Introduction:
Acceleration is rate of change of velocity. Negative acceleration is called retardation.
Velocity is rate of change of displacement with respect to time. When breaks are applied auto velocity goes on decreasing that is acceleration of auto is negative. Auto is decelerating. So autos velocity and acceleration are in opposite direction.
Conclusion:
Therefore, a person will agree that auto’s velocity and acceleration are in opposite direction.
Chapter 6 Solutions
Conceptual Physics: The High School Physics Program
Additional Science Textbook Solutions
Campbell Biology (11th Edition)
Chemistry: Structure and Properties (2nd Edition)
Anatomy & Physiology (6th Edition)
Chemistry (7th Edition)
Microbiology with Diseases by Body System (5th Edition)
Microbiology: An Introduction
- No chatgpt plsarrow_forwardConsider the situation in the figure below; a neutral conducting ball hangs from the ceiling by an insulating string, and a charged insulating rod is going to be placed nearby. A. First, if the rod was not there, what statement best describes the charge distribution of the ball? 1) Since it is a conductor, all the charges are on the outside of the ball. 2) The ball is neutral, so it has no positive or negative charges anywhere. 3) The positive and negative charges are separated from each other, but we don't know what direction the ball is polarized. 4) The positive and negative charges are evenly distributed everywhere in the ball. B. Now, when the rod is moved close to the ball, what happens to the charges on the ball? 1) There is a separation of charges in the ball; the side closer to the rod becomes positively charged, and the opposite side becomes negatively charged. 2) Negative charge is drawn from the ground (via the string), so the ball acquires a net negative charge. 3)…arrow_forwardanswer question 5-9arrow_forward
- AMPS VOLTS OHMS 5) 50 A 110 V 6) .08 A 39 V 7) 0.5 A 60 8) 2.5 A 110 Varrow_forwardThe drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m², while surface (2) has an area of 3.90 m². The electric field in the drawing is uniform and has a magnitude of 215 N/C. Find the magnitude of the electric flux through surface (1 and 2 combined) if the angle 8 made between the electric field with surface (2) is 30.0°. Solve in Nm²/C 1 Ө Surface 2 Surface 1arrow_forwardPROBLEM 5 What is the magnitude and direction of the resultant force acting on the connection support shown here? F₁ = 700 lbs F2 = 250 lbs 70° 60° F3 = 700 lbs 45° F4 = 300 lbs 40° Fs = 800 lbs 18° Free Body Diagram F₁ = 700 lbs 70° 250 lbs 60° F3= = 700 lbs 45° F₁ = 300 lbs 40° = Fs 800 lbs 18°arrow_forward
- PROBLEM 3 Cables A and B are Supporting a 185-lb wooden crate. What is the magnitude of the tension force in each cable? A 20° 35° 185 lbsarrow_forwardThe determined Wile E. Coyote is out once more to try to capture the elusive Road Runner of Loony Tunes fame. The coyote is strapped to a rocket, which provide a constant horizontal acceleration of 15.0 m/s2. The coyote starts off at rest 79.2 m from the edge of a cliff at the instant the roadrunner zips by in the direction of the cliff. If the roadrunner moves with constant speed, find the minimum velocity the roadrunner must have to reach the cliff before the coyote. (proper sig fig in answer)arrow_forwardPROBLEM 4 What is the resultant of the force system acting on the connection shown? 25 F₁ = 80 lbs IK 65° F2 = 60 lbsarrow_forward
- Three point-like charges in the attached image are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 38.0 cm, and the point (C) is located half way between q1 and q3 along the side. Find the magnitude of the electric field at point (C). Let q1 = −2.80 µC, q2 = −3.40 µC, and q3 = −4.50 µC. Thank you.arrow_forwardSTRUCTURES I Homework #1: Force Systems Name: TA: PROBLEM 1 Determine the horizontal and vertical components of the force in the cable shown. PROBLEM 2 The horizontal component of force F is 30 lb. What is the magnitude of force F? 6 10 4 4 F = 600lbs F = ?arrow_forwardThe determined Wile E. Coyote is out once more to try to capture the elusive Road Runner of Loony Tunes fame. The coyote is strapped to a rocket, which provide a constant horizontal acceleration of 15.0 m/s2. The coyote starts off at rest 79.2 m from the edge of a cliff at the instant the roadrunner zips by in the direction of the cliff. If the roadrunner moves with constant speed, find the minimum velocity the roadrunner must have to reach the cliff before the coyote. (proper sig fig)arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON