Use the exact values you enter in previous answer(s) to make later calculation(s). Consider the following figure. (Assume R₁ = 31.0 £2, R2 = 19.0 £2, and V = 16.0 V.) V + 10.0 V |+ R₁ ww 5.00 Ω W R₂ (a) Can the circuit shown above be reduced to a single resistor connected to the batteries? Explain. This answer has not been graded yet. (b) Find the magnitude of the current and its direction in each resistor. R2: 19.0 2.253 ХА 5.00 Ω = -.624 ХА R₁: : 31.0 Ω =-.371 ХА
Use the exact values you enter in previous answer(s) to make later calculation(s). Consider the following figure. (Assume R₁ = 31.0 £2, R2 = 19.0 £2, and V = 16.0 V.) V + 10.0 V |+ R₁ ww 5.00 Ω W R₂ (a) Can the circuit shown above be reduced to a single resistor connected to the batteries? Explain. This answer has not been graded yet. (b) Find the magnitude of the current and its direction in each resistor. R2: 19.0 2.253 ХА 5.00 Ω = -.624 ХА R₁: : 31.0 Ω =-.371 ХА
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter28: Current And Resistance
Section: Chapter Questions
Problem 67PQ
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Transcribed Image Text:Use the exact values you enter in previous answer(s) to make later calculation(s).
Consider the following figure. (Assume R₁ = 31.0 £2, R2 = 19.0 £2, and V = 16.0 V.)
V
+
10.0 V
|+
R₁
ww
5.00 Ω
W
R₂
(a) Can the circuit shown above be reduced to a single resistor connected to the batteries? Explain.
This answer has not been graded yet.
(b) Find the magnitude of the current and its direction in each resistor.
R2: 19.0 2.253
ХА
5.00 Ω
= -.624
ХА
R₁:
: 31.0 Ω
=-.371
ХА

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