A1. Provide a diagram here A2. the horizontal component of velocity at kick-off B. the vertical component of velocity at kick-off C. the maximum height reached by the ball A player kicks a football at the start of the game. After a 4 second flight, the ball touches the ground 50 m from the kicking tee. Assume air resistance is negligible and the take-off and landing height are the same (i.e., time to peak = time to fall = ½ total flight time). (Note: For each question draw a diagram to show the vector/s. Show all the step and provide units in the answers. Provide answer to 2 decimal places unless stated otherwise.) Calculate and answer all parts. Only use equations PROVIDED: Only equations to be used: • Vertical (y) direction = Vfy = Viy + ay*t, Vfy = Viy + (g) * t • Position final = Position initial + Velocity initial * time + ½ acceleration * time^2, Horizontal in (x) direction is sfx = S(ix) + V(ix)*t, V(ix) = s(fx) - s(ix)/time or s(fx) = s(ix) = v(ix) * time, vertical (y) direction is s(fy) = s(iy) + v(iy) * time + ½ g * t^2, • • • Vertical direction, displacement is Sfy-Siy = Viy * t + ½ g * t^2, Formula for vertical in (y) direction is Sfy Siy+Vy *t+ ½ g *t^2. Equation for the vertical (y) direction displacement is (Sfy - Siy) = Viy * t + ½ g*t [Velocity final]^2 = [velocity initial] ^2+2 * acceleration * (position final - position initial), formula for this is v2f=v2i + 2 a (Sf-si) For horizontal x direction formula is Vfx = Vix, for vertical (y) direction formula is V2fy = V2iy + 2g (Sfy - Siy), Vertical displacement is (Sfy - Siy)= -vi2iy/2g * Horizontal distance travelled (Range = VH * airborne time) A1. Provide a diagram here A2. the horizontal component of velocity at kick-off
A1. Provide a diagram here A2. the horizontal component of velocity at kick-off B. the vertical component of velocity at kick-off C. the maximum height reached by the ball A player kicks a football at the start of the game. After a 4 second flight, the ball touches the ground 50 m from the kicking tee. Assume air resistance is negligible and the take-off and landing height are the same (i.e., time to peak = time to fall = ½ total flight time). (Note: For each question draw a diagram to show the vector/s. Show all the step and provide units in the answers. Provide answer to 2 decimal places unless stated otherwise.) Calculate and answer all parts. Only use equations PROVIDED: Only equations to be used: • Vertical (y) direction = Vfy = Viy + ay*t, Vfy = Viy + (g) * t • Position final = Position initial + Velocity initial * time + ½ acceleration * time^2, Horizontal in (x) direction is sfx = S(ix) + V(ix)*t, V(ix) = s(fx) - s(ix)/time or s(fx) = s(ix) = v(ix) * time, vertical (y) direction is s(fy) = s(iy) + v(iy) * time + ½ g * t^2, • • • Vertical direction, displacement is Sfy-Siy = Viy * t + ½ g * t^2, Formula for vertical in (y) direction is Sfy Siy+Vy *t+ ½ g *t^2. Equation for the vertical (y) direction displacement is (Sfy - Siy) = Viy * t + ½ g*t [Velocity final]^2 = [velocity initial] ^2+2 * acceleration * (position final - position initial), formula for this is v2f=v2i + 2 a (Sf-si) For horizontal x direction formula is Vfx = Vix, for vertical (y) direction formula is V2fy = V2iy + 2g (Sfy - Siy), Vertical displacement is (Sfy - Siy)= -vi2iy/2g * Horizontal distance travelled (Range = VH * airborne time) A1. Provide a diagram here A2. the horizontal component of velocity at kick-off
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Question
A player kicks a football at the start of the game. After a 4 second flight, the ball touches the ground 50 m from the kicking tee. Assume air resistance is negligible and the take-off and landing height are the same (i.e., time to peak = time to fall = ½ total flight time). (Note: For each question draw a diagram to show the vector/s. Show all the step and provide units in the answers. Provide answer to 2 decimal places unless stated otherwise.) Calculate and answer all parts. Only use equations PROVIDED:

Transcribed Image Text:A1. Provide a diagram here
A2. the horizontal component of velocity at kick-off
B. the vertical component of velocity at kick-off
C. the maximum height reached by the ball
![A player kicks a football at the start of the game. After a 4 second flight, the ball touches the ground 50 m from
the kicking tee. Assume air resistance is negligible and the take-off and landing height are the same (i.e., time to
peak = time to fall = ½ total flight time). (Note: For each question draw a diagram to show the vector/s. Show
all the step and provide units in the answers. Provide answer to 2 decimal places unless stated otherwise.)
Calculate and answer all parts. Only use equations PROVIDED:
Only equations to be used:
•
Vertical (y) direction = Vfy = Viy + ay*t, Vfy = Viy + (g) * t
• Position final = Position initial + Velocity initial * time + ½ acceleration * time^2, Horizontal in (x)
direction is sfx = S(ix) + V(ix)*t, V(ix) = s(fx) - s(ix)/time or s(fx) = s(ix) = v(ix) * time, vertical (y)
direction is s(fy) = s(iy) + v(iy) * time + ½ g * t^2,
•
•
•
Vertical direction, displacement is Sfy-Siy = Viy * t + ½ g * t^2, Formula for vertical in (y) direction is
Sfy Siy+Vy *t+ ½ g *t^2. Equation for the vertical (y) direction displacement is (Sfy - Siy) = Viy
* t + ½ g*t
[Velocity final]^2 = [velocity initial] ^2+2 * acceleration * (position final - position initial), formula for
this is v2f=v2i + 2 a (Sf-si)
For horizontal x direction formula is Vfx = Vix, for vertical (y) direction formula is V2fy = V2iy + 2g
(Sfy - Siy), Vertical displacement is (Sfy - Siy)= -vi2iy/2g
* Horizontal distance travelled (Range = VH * airborne time)
A1. Provide a diagram here
A2. the horizontal component of velocity at kick-off](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F14055f04-58ff-4c00-af23-66e4ceb29afb%2F46ec4a38-ca4d-4dbb-8d20-649e8cc75325%2F5sm6s5_processed.png&w=3840&q=75)
Transcribed Image Text:A player kicks a football at the start of the game. After a 4 second flight, the ball touches the ground 50 m from
the kicking tee. Assume air resistance is negligible and the take-off and landing height are the same (i.e., time to
peak = time to fall = ½ total flight time). (Note: For each question draw a diagram to show the vector/s. Show
all the step and provide units in the answers. Provide answer to 2 decimal places unless stated otherwise.)
Calculate and answer all parts. Only use equations PROVIDED:
Only equations to be used:
•
Vertical (y) direction = Vfy = Viy + ay*t, Vfy = Viy + (g) * t
• Position final = Position initial + Velocity initial * time + ½ acceleration * time^2, Horizontal in (x)
direction is sfx = S(ix) + V(ix)*t, V(ix) = s(fx) - s(ix)/time or s(fx) = s(ix) = v(ix) * time, vertical (y)
direction is s(fy) = s(iy) + v(iy) * time + ½ g * t^2,
•
•
•
Vertical direction, displacement is Sfy-Siy = Viy * t + ½ g * t^2, Formula for vertical in (y) direction is
Sfy Siy+Vy *t+ ½ g *t^2. Equation for the vertical (y) direction displacement is (Sfy - Siy) = Viy
* t + ½ g*t
[Velocity final]^2 = [velocity initial] ^2+2 * acceleration * (position final - position initial), formula for
this is v2f=v2i + 2 a (Sf-si)
For horizontal x direction formula is Vfx = Vix, for vertical (y) direction formula is V2fy = V2iy + 2g
(Sfy - Siy), Vertical displacement is (Sfy - Siy)= -vi2iy/2g
* Horizontal distance travelled (Range = VH * airborne time)
A1. Provide a diagram here
A2. the horizontal component of velocity at kick-off
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