Chapter 6, Problem 6G.5E

Interpretation Introduction

Interpretation:

From the given data, the activation energy for the motion of water molecules has to be calculated.

Concept Introduction:

Activation energy$(E_a)$: The potential energy barrier that must be surmounted before reactants can be converted to products.

Arrhenius equation:

• Arrhenius equation is a formula that represents the temperature dependence of reaction rates
• The Arrhenius equation has to be represented as follows $f=e^{-E_a/RT}$
• $E_a$ represents the activation energy and it’s unit is kJ/mol
• R represents the universal gas constant and it has the value of $\text{8}\text{.314 J/K}\text{.mol}$
• T represents the absolute temperature
• f represents the frequency factor or collision frequency

The activation energy from the given information has to be calculated from the modified Arrhenius equation.

  $\text{ln}\frac{{\text{k}}_{\text{1}}}{{\text{k}}_{\text{2}}}\text{=}\frac{{\text{E}}_{\text{a}}}{\text{R}}\left[\frac{\text{1}}{{\text{T}}_{\text{2}}}\text{-}\frac{\text{1}}{{\text{T}}_{\text{1}}}\right]$

Viscosity: It is $\eta$ defined by ratio of force per wall area to the velocity gradient.

Example: $F=A\eta \frac{\nu }{h}$