Chapter 6, Problem 6.25P

Interpretation Introduction

Interpretation:

Michaelis and Menten derived their rate law by assuming a rapid pre-equilibrium of $E,S$ and $ES$; the rate law in this manner has to be derived. The condition under which it becomes the same as that based on the steady state approximation has to be identified.

Concept Introduction:

The rate of reaction is the quantity of formation of product or the quantity of reactant used per unit time. The rate of reaction doesn’t depend on the sum of amount of reaction mixture used.

The raise in molar concentration of product of a reaction per unit time or decrease in molarity of reactant per unit time is called rate of reaction and is expressed in units of $\text{mol/(L}\text{.s)}$ .

Steady state approximation: This method used to derive a rate law. The method is based on the assumption that one intermediate in the reaction mechanism is consumed as quickly as it is generated.

Example: Use the SSA approximate to calculate the concentration of the intermediate $\left(C\right)$ in the following sequence of elementary steps.

  $\begin{array}{l}A+B\underset{k_2}{\overset{k_1}{\rightleftharpoons }}C\\ C\stackrel{k_2}{\to }D\end{array}$

Where the rate constant $\left(k_r\right)$ is indicated, the overall reaction is.

$A+B\stackrel{}{\to }D$