Chapter 6, Problem 6C.3E

Interpretation Introduction

Interpretation:

The rate constant for the given decarboxylase enzyme reaction has to be calculated.

Concept Introduction:

Partial pressure: The pressure of each gas in a mixture of gases is the partial pressure.

The partial pressure of a gas in a mixture can be expressed as,

$\begin{array}{l}{\text{P}}_{\text{A}}={\text{X}}_{\text{A}}{\text{P}}_{\text{Total}}\\ {\text{P}}_{\text{A}}\to \text{Partial}\text{pressure}\text{of}\text{gas}\text{A}\\ {\text{X}}_{\text{A}}\to \text{Mole}\text{fraction}\text{of}\text{gas}\text{A}\\ {\text{P}}_{\text{Total}}\to \text{Total}\text{pressure}\text{of}\text{mixture}\end{array}$

Rate of a reaction: It represents the speed at which a chemical reaction runs.  How much concentration of substrates (reactants) consumed and how much concentration of targets (products) formed in a unit of time is said to be rate of reaction.

Order of a reaction:  The sum of exponents of the concentrations in the rate law for the reaction is said to be order of a reaction.

$\text{Order}\text{= }\text{x+y}$

Half-life is the time required for one half of a reactant to react.

For first order reaction $\begin{array}{l}-kt=\ln \left(\frac{\left[A\right]}{\left[A_0\right]}\right)\\ (or)k=\frac{1}{t}\ln \frac{\left[A\right]}{\left[A_0\right]}\end{array}$

$\left[A\right]$ is the concentration of reactant A at time t ${\left[A\right]}_0$ is the  initial concentration of reactant, k is the rate constant.