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(a)
Interpretation:
The mass of Helium in the balloon has to be calculated.
Concept Introduction:
At constant temperature, (Boyle’s law)
At constant volume, (Charles’s law)
By combining the above equations,
Where R= proportionality constant called as gas constant.
The general equation for ideal gas law is written as,
Where n= number of moles
(a)
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Answer to Problem 6.95QP
The mass of Helium in the balloon is
Explanation of Solution
Given,
Diameter of balloon is
Temperature of inflation is
The volume of balloon is calculated as,
The mass of Helium is calculated as,
The mass of Helium in the balloon is
(b)
Interpretation:
The work done in joules has to be calculated.
Concept Introduction:
The work done on the system or by the system can be calculated from the equation
Where w=work done
P=Pressure
(b)
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Answer to Problem 6.95QP
The work done in joules is
Explanation of Solution
Given,
Diameter of balloon is
Temperature of inflation is
Pressure is
The volume of balloon is calculated as,
The work done is calculated as,
The work done in joules is
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Chapter 6 Solutions
General Chemistry
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