General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 6, Problem 6.81QP
Interpretation Introduction

Interpretation:

The volume of ethane that is required to heat the mass of water has to be given.

Concept Introduction:

The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation

(ΔHf°).  The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.

The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.

The equation for determining the standard enthalpies of compound and element can be given by,

ΔH°reaction=nΔH°f(products)-mΔH°f(reactants)

Specific heat:

Specific heat can be defined as quantity of heat required to raise the temperature of 1g substance by 1°C.  The relationship between heat and change in temperature can be expressed by the equation given below.

q=cmΔT

Where q= Heat added

c= Specific heat

m= Mass

ΔT= Change in temperature.

The unit of specific heat is Jg-1.°C .

Expert Solution & Answer
Check Mark

Answer to Problem 6.81QP

The volume of ethane that is required to heat the mass of water is 4.10L.

Explanation of Solution

The combustion reaction is given as,

C2H6(l)+72O2(g)2CO2(g)+3H2O(l)

The heat released during the combustion is calculated as,

ΔH°rxtn = [2ΔH°f(CO2)+3ΔH°f(H2O)]-[ΔH°f(C2H6)+72ΔH°f(O2)]ΔH°rxtn = [(2)(-393.5kJ/mole)+(3)(-285.8kJ/mole)]-[(1)(-84.7kJ/mole)+72(O2)]ΔH°rxtn = -1560kJ/mole

The heat requires to raise the temperature of water to 98°C is calculated as,

q = mH2OsH2OΔtq = (855g)(4.184J/g°C)(98.0-25.0)°Cq = 2.61×105Jq = 261kJ

The combustion of one mole of ethane yields 1560kJ , the number of moles of ethane is calculated as,

Numberofmoles of ethane = 261kJ×1moleethane1560kJNumberofmoles of ethane = 0.167mole

The volume of ethane is calculated using the ideal gas equation,

PV = nRTVethane = nRTPVethane = (0.167mole)(0.0821L.atmmole.K)(296K)(752mmHg×1atm760mmHg)Vethane = 4.10L

The volume of ethane that is required to heat the mass of water is 4.10L.

Conclusion

The volume of ethane that is required to heat the mass of water was calculated as 4.10L.

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Chapter 6 Solutions

General Chemistry

Ch. 6.5 - Prob. 4PECh. 6.5 - Prob. 1RCCh. 6.6 - Prob. 1PECh. 6.6 - Prob. 2PECh. 6.6 - Prob. 1RCCh. 6 - Prob. 6.1QPCh. 6 - Prob. 6.2QPCh. 6 - Prob. 6.3QPCh. 6 - Prob. 6.4QPCh. 6 - Prob. 6.5QPCh. 6 - Prob. 6.7QPCh. 6 - Prob. 6.8QPCh. 6 - Prob. 6.9QPCh. 6 - Prob. 6.10QPCh. 6 - Prob. 6.11QPCh. 6 - Prob. 6.12QPCh. 6 - 6. 13 The internal energy of an ideal gas depends...Ch. 6 - 6.14 Consider these changes. At constant...Ch. 6 - Prob. 6.15QPCh. 6 - Prob. 6.16QPCh. 6 - Prob. 6.17QPCh. 6 - Prob. 6.18QPCh. 6 - 6.19 Calculate the work done when 50.0 g of tin...Ch. 6 - Prob. 6.20QPCh. 6 - Prob. 6.21QPCh. 6 - Prob. 6.22QPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - 6.26 Determine the amount of heat (in kJ) given...Ch. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - 6.46 The values of the two allotropes of oxygen,...Ch. 6 - 6.47 Which is the more negative quantity at 25°C: ...Ch. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - 6.58 The first step in the industrial recovery or...Ch. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106SPCh. 6 - Prob. 6.107SPCh. 6 - Prob. 6.109SPCh. 6 - Prob. 6.110SPCh. 6 - Prob. 6.111SPCh. 6 - Prob. 6.112SPCh. 6 - Prob. 6.113SPCh. 6 - Prob. 6.114SPCh. 6 - Prob. 6.115SPCh. 6 - Prob. 6.116SPCh. 6 - Prob. 6.117SPCh. 6 - Prob. 6.118SP
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