General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 6, Problem 6.14QP

(a)

Interpretation Introduction

Interpretation:

For the given reaction, the work done by the system on the surroundings, work done by the surroundings on the system and no work done has to be identified.

Concept introduction:

First law of thermodynamics:

The first law of thermodynamics states that energy can be either destroyed or created but instead it can be converted from one form to other.

The equation for the first law of thermodynamics can be given as,

ΔU=q+w

  • If system gains heat, then q= positive.
  • If work is done on the system, then w= positive.
  • If system loses heat, then q= negative.
  • If work is done by the system, then w= negative.

(b)

Interpretation Introduction

Interpretation:

For the given reaction, the work done by the system on the surroundings, work done by the surroundings on the system and no work done has to be identified.

Concept introduction:

First law of thermodynamics:

The first law of thermodynamics states that energy can be either destroyed or created but instead it can be converted from one form to other.

The equation for the first law of thermodynamics can be given as,

ΔU=q+w

  • If system gains heat, then q= positive.
  • If work is done on the system, then w= positive.
  • If system loses heat, then q= negative.
  • If work is done by the system, then w= negative.

(c)

Interpretation Introduction

Interpretation:

For the given reaction, the work done by the system on the surroundings, work done by the surroundings on the system and no work done has to be identified.

Concept introduction:

First law of thermodynamics:

The first law of thermodynamics states that energy can be either destroyed or created but instead it can be converted from one form to other.

The equation for the first law of thermodynamics can be given as,

ΔU=q+w

  • If system gains heat, then q= positive.
  • If work is done on the system, then w= positive.
  • If system loses heat, then q= negative.
  • If work is done by the system, then w= negative.

(d)

Interpretation Introduction

Interpretation:

For the given reaction, the work done by the system on the surroundings, work done by the surroundings on the system and no work done has to be identified.

Concept introduction:

First law of thermodynamics:

The first law of thermodynamics states that energy can be either destroyed or created but instead it can be converted from one form to other.

The equation for the first law of thermodynamics can be given as,

ΔU=q+w

  • If system gains heat, then q= positive.
  • If work is done on the system, then w= positive.
  • If system loses heat, then q= negative.
  • If work is done by the system, then w= negative.

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ion. A student proposes the following Lewis structure for the perchlorate (CIO) io : :0: : Cl : - - : :0: ك Assign a formal charge to each atom in the student's Lewis structure. atom central O formal charge ☐ top O ☐ right O ☐ bottom O ☐ Cl ☐
Decide whether these proposed Lewis structures are reasonable. proposed Lewis structure Yes. Is the proposed Lewis structure reasonable? Cl- : 2: :Z: :Z: N—N : 0: C C1: O CO No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* ☐ Yes. No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0". ☑
Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions ΔΗ is (pick one) A This reaction is faster above 103. °C than below. AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous only above -9. °C. AS is (pick one) ΔΗ is (pick one) C The reverse of this reaction is always spontaneous. AS is (pick one) 18 Ar

Chapter 6 Solutions

General Chemistry

Ch. 6.5 - Prob. 4PECh. 6.5 - Prob. 1RCCh. 6.6 - Prob. 1PECh. 6.6 - Prob. 2PECh. 6.6 - Prob. 1RCCh. 6 - Prob. 6.1QPCh. 6 - Prob. 6.2QPCh. 6 - Prob. 6.3QPCh. 6 - Prob. 6.4QPCh. 6 - Prob. 6.5QPCh. 6 - Prob. 6.7QPCh. 6 - Prob. 6.8QPCh. 6 - Prob. 6.9QPCh. 6 - Prob. 6.10QPCh. 6 - Prob. 6.11QPCh. 6 - Prob. 6.12QPCh. 6 - 6. 13 The internal energy of an ideal gas depends...Ch. 6 - 6.14 Consider these changes. At constant...Ch. 6 - Prob. 6.15QPCh. 6 - Prob. 6.16QPCh. 6 - Prob. 6.17QPCh. 6 - Prob. 6.18QPCh. 6 - 6.19 Calculate the work done when 50.0 g of tin...Ch. 6 - Prob. 6.20QPCh. 6 - Prob. 6.21QPCh. 6 - Prob. 6.22QPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - 6.26 Determine the amount of heat (in kJ) given...Ch. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - 6.46 The values of the two allotropes of oxygen,...Ch. 6 - 6.47 Which is the more negative quantity at 25°C: ...Ch. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - 6.58 The first step in the industrial recovery or...Ch. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106SPCh. 6 - Prob. 6.107SPCh. 6 - Prob. 6.109SPCh. 6 - Prob. 6.110SPCh. 6 - Prob. 6.111SPCh. 6 - Prob. 6.112SPCh. 6 - Prob. 6.113SPCh. 6 - Prob. 6.114SPCh. 6 - Prob. 6.115SPCh. 6 - Prob. 6.116SPCh. 6 - Prob. 6.117SPCh. 6 - Prob. 6.118SP
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