General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 6, Problem 6.102QP

(a)

Interpretation Introduction

Interpretation:

The equation for the formation of Acetylene and the maximum amount of heat from combustion of Acetylene has to be calculated.

Concept Introduction:

The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation (ΔHf°).  The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.

The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.

 The equation for determining the standard enthalpies of compound and element can be given by,

ΔH°reaction=nΔH°f(products)-mΔH°f(reactants)

(a)

Expert Solution
Check Mark

Answer to Problem 6.102QP

CaC2(s)+2H2O(l)Ca(OH)2(s)+C2H(g)

Explanation of Solution

Calcium carbide upon reaction with Water gives Calcium hydroxide and Acetylene. The chemical reaction can be given as,

CaC2(s)+2H2O(l)Ca(OH)2(s)+C2H(g)

(b)

Interpretation Introduction

Interpretation:

The equation for the formation of Acetylene and the maximum amount of heat from combustion of Acetylene has to be calculated.

Concept Introduction:

The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation (ΔHf°).  The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.

The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.

 The equation for determining the standard enthalpies of compound and element can be given by,

ΔH°reaction=nΔH°f(products)-mΔH°f(reactants)

(b)

Expert Solution
Check Mark

Answer to Problem 6.102QP

The maximum amount of heat obtained is 1.51×106J

Explanation of Solution

The combustion reaction of Acetylene can be given as,

2C2H2(g)+5O2(g)4CO2(g)+2H2O(l)

Standard enthalpy of formation of CO2=-393.5kJmol1

Standard enthalpy of formation of H2O=-285.8kJmol-1

Standard enthalpy of formation of O2=0kJmol-1

Standard enthalpy of formation of C2H5=-226.6kJmol-1

ΔH°reaction=[4ΔH°f(CO2)+2ΔH°f(H2O)]-[2ΔH°f(C2H5)+5ΔH°f(O2)]ΔH°reaction=[(4)(-393.5kJmol-1)+(2)(-285.8kJmol-1)]-[(2)(226.6kJmol-1)+(5)(0)]ΔH°reaction=-2599kJmol-1

Enthalpy of reaction= -2599kJmol-1

To calculate the moles of C2H2

Moles of C2H2= 74.6gCaC2×1molCaC264.10gCaC2×1molC2H21molCaC2

Moles of C2H2=1.16mol

To calculate the amount in heat for 1.16mol of C2H2

Amount of heat = 1.16molC2H2×2599kJ2molC2H2

Amount of heat =1.51×103kJ=1.51×106J

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Chapter 6 Solutions

General Chemistry

Ch. 6.5 - Prob. 4PECh. 6.5 - Prob. 1RCCh. 6.6 - Prob. 1PECh. 6.6 - Prob. 2PECh. 6.6 - Prob. 1RCCh. 6 - Prob. 6.1QPCh. 6 - Prob. 6.2QPCh. 6 - Prob. 6.3QPCh. 6 - Prob. 6.4QPCh. 6 - Prob. 6.5QPCh. 6 - Prob. 6.7QPCh. 6 - Prob. 6.8QPCh. 6 - Prob. 6.9QPCh. 6 - Prob. 6.10QPCh. 6 - Prob. 6.11QPCh. 6 - Prob. 6.12QPCh. 6 - 6. 13 The internal energy of an ideal gas depends...Ch. 6 - 6.14 Consider these changes. At constant...Ch. 6 - Prob. 6.15QPCh. 6 - Prob. 6.16QPCh. 6 - Prob. 6.17QPCh. 6 - Prob. 6.18QPCh. 6 - 6.19 Calculate the work done when 50.0 g of tin...Ch. 6 - Prob. 6.20QPCh. 6 - Prob. 6.21QPCh. 6 - Prob. 6.22QPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - 6.26 Determine the amount of heat (in kJ) given...Ch. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - 6.46 The values of the two allotropes of oxygen,...Ch. 6 - 6.47 Which is the more negative quantity at 25°C: ...Ch. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - 6.58 The first step in the industrial recovery or...Ch. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106SPCh. 6 - Prob. 6.107SPCh. 6 - Prob. 6.109SPCh. 6 - Prob. 6.110SPCh. 6 - Prob. 6.111SPCh. 6 - Prob. 6.112SPCh. 6 - Prob. 6.113SPCh. 6 - Prob. 6.114SPCh. 6 - Prob. 6.115SPCh. 6 - Prob. 6.116SPCh. 6 - Prob. 6.117SPCh. 6 - Prob. 6.118SP
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