General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 6, Problem 6.93QP

(a)

Interpretation Introduction

Interpretation:

The final temperature of the product and the standard enthalpy of formation of Ca(OH)2 has to be calculated.

Concept Introduction:

Specific heat can be defined as quantity of heat required to raise the temperature of 1g substance by 1°C.  The relationship between heat and change in temperature can be expressed by the equation given below.

q=smΔT

Where,

q= Heat added

s = Specific heat

m= Mass

ΔT= Change in temperature.

The unit of specific heat is Jg-1.°C.

(a)

Expert Solution
Check Mark

Answer to Problem 6.93QP

The final temperature is 758°C .

Explanation of Solution

To calculate the moles of H2O

Mass of Water = 500g

Moles of Water = 5001molH2O18.02gH2O

=27.75mol

Moles of Water =27.75mol

To calculate the heat generated by the reaction

Moles of Water =27.75mol

Enthalpy of production of Ca(OH)2= -65.2kJ

Heat generated = 27.75molCa(OH)2×-65.2kJ1molCa(OH)2

= -1.809×103kJ

Heat generated by the reaction=-1.809×103kJ

To calculate the mass of Ca(OH)2 in 27.75molCa(OH)2

Mass of Ca(OH)2=27.75mol Ca(OH)2×74.10gCa(OH)21molCa(OH)2

= 2.056×103g

Mass of Ca(OH)2=2.056×103g

To calculate the final temperature

q=smΔT

Rearranging we get,

ΔT=qmsΔT=1.809×106J(2.056×103g)(1.20Jg-1°C)=733°CΔT=Tinitial-TfinalΔT=(733+25)°CΔT=758°C

Final temperature of the product = 758°C

(b)

Interpretation Introduction

Concept Introduction:

The change in enthalpy that is associated with the formation of one mole of a substance from its related elements being in standard state is called standard enthalpy of formation (ΔHf°).  The standard enthalpy of formation is used to determine the standard enthalpies of compound and element.

The standard enthalpy of reaction is the enthalpy of reaction that takes place under standard conditions.

 The equation for determining the standard enthalpies of compound and element can be given by,

ΔH°reaction=nΔH°f(products)-mΔH°f(reactants)

(b)

Expert Solution
Check Mark

Answer to Problem 6.93QP

The standard enthalpy of formation is -986.6kJmol-1 .

Explanation of Solution

The reaction can be given as,

CaO(s)+H2O(l)Ca(OH)2(s)

Enthalpy of reaction = -65.2kJmol-1

Standard enthalpy of formation of CaO=-635.6kJmol1

Standard enthalpy of formation of H2O=-285.8kJmol-1

Standard enthalpy of formation of Ca(OH)2,

ΔHreaction=ΔH°f[Ca(OH)2]-[ΔH°f(CaO)+ΔH°f(H2O)]-65.2kJmol-1=ΔH°f[Ca(OH)2]-[(1)(-635.6kJmol-1)+(1)(-285.8kJmol-1)]ΔH°f[Ca(OH)2]=-986.6kJmol-1

Standard enthalpy of formation of Ca(OH)2=-986.6kJmol-1

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Chapter 6 Solutions

General Chemistry

Ch. 6.5 - Prob. 4PECh. 6.5 - Prob. 1RCCh. 6.6 - Prob. 1PECh. 6.6 - Prob. 2PECh. 6.6 - Prob. 1RCCh. 6 - Prob. 6.1QPCh. 6 - Prob. 6.2QPCh. 6 - Prob. 6.3QPCh. 6 - Prob. 6.4QPCh. 6 - Prob. 6.5QPCh. 6 - Prob. 6.7QPCh. 6 - Prob. 6.8QPCh. 6 - Prob. 6.9QPCh. 6 - Prob. 6.10QPCh. 6 - Prob. 6.11QPCh. 6 - Prob. 6.12QPCh. 6 - 6. 13 The internal energy of an ideal gas depends...Ch. 6 - 6.14 Consider these changes. At constant...Ch. 6 - Prob. 6.15QPCh. 6 - Prob. 6.16QPCh. 6 - Prob. 6.17QPCh. 6 - Prob. 6.18QPCh. 6 - 6.19 Calculate the work done when 50.0 g of tin...Ch. 6 - Prob. 6.20QPCh. 6 - Prob. 6.21QPCh. 6 - Prob. 6.22QPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - 6.26 Determine the amount of heat (in kJ) given...Ch. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - 6.46 The values of the two allotropes of oxygen,...Ch. 6 - 6.47 Which is the more negative quantity at 25°C: ...Ch. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - 6.58 The first step in the industrial recovery or...Ch. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106SPCh. 6 - Prob. 6.107SPCh. 6 - Prob. 6.109SPCh. 6 - Prob. 6.110SPCh. 6 - Prob. 6.111SPCh. 6 - Prob. 6.112SPCh. 6 - Prob. 6.113SPCh. 6 - Prob. 6.114SPCh. 6 - Prob. 6.115SPCh. 6 - Prob. 6.116SPCh. 6 - Prob. 6.117SPCh. 6 - Prob. 6.118SP
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