Applied Fluid Mechanics (7th Edition)
7th Edition
ISBN: 9780132558921
Author: Robert L. Mott, Joseph A. Untener
Publisher: PEARSON
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Textbook Question
Chapter 6, Problem 6.72PP
For the siphon shown in Fig. 6.27, calculate (a) the volume flow rate of oil from the tank and (b) the pressures at points A, B, C, and D.
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Hydraulic Machines
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The plunger diameter of a single-acting reciprocating pump is 115 mm and the stroke is 230 mm. The suction pipe is 90 mm in diameter and 4.2 m long. If cavitation takes place at the suction head of 4 m, the barometer stands at 10.3 m of water, and the water level in the sump is 3 m below the pump cylinder axis.1. Find the maximum allowable speed to operate the pump
The plunger diameter of a single-acting reciprocating pump is 115 mm and the stroke
is 230 mm. The suction pipe is 90 mm in diameter and 4.2 m long. If cavitation takes
place at the suction head of 4 m, the barometer stands at 10.3 m of water, and the
water level in the sump is 3 m below the pump cylinder axis.
3.1 Find the maximum allowable speed to operate the pump
3.2 What power is expected in overcoming friction at this speed, takef = 0.01
Chapter 6 Solutions
Applied Fluid Mechanics (7th Edition)
Ch. 6 - Convert a volume flow rate of 3.0 gal/min to...Ch. 6 - Convert 459 gal/min to rrP/s.Ch. 6 - Convert 3720 gal/min to mJ/sCh. 6 - Convert 34.3 gal/min to mJ/sCh. 6 - Convert a volume flow rate of 125 L/min to m3/s.Ch. 6 - Convert 4500 L/min to m5/s.Ch. 6 - Convert 15 000 L/minto m3/s.Ch. 6 - Convert 459 gal/min to L/mninCh. 6 - Convert 3720 gal/min to L/minCh. 6 - Convert 23.5cm2/stom3/s.
Ch. 6 - '6.11 Convert 0.296cm5/stom3/s.Ch. 6 - Convert 0.105 cm3/s to L/minCh. 6 - Convert 3.53103m3/s to L/min.Ch. 6 - Convert 5.26106m3stoL/min.Ch. 6 - Prob. 6.15PPCh. 6 - Convert 20 gal/min to ft'/s.Ch. 6 - Convert 2500 gal/min to ft5/s.Ch. 6 - Convert 2.50 gal/min to ft3/s.Ch. 6 - Convert 125 ft3/s to gal/minCh. 6 - Convert 0.060 ft3/s to gal/min.Ch. 6 - Convert 0.03 ft5/s to gal/minCh. 6 - Convert ft5/s sto gal/minCh. 6 - Table 6.21 lists the range of typical volume flow...Ch. 6 - Table 6.2 lists the range of typical volume flow...Ch. 6 - A certain deep-well pump for a residence is rated...Ch. 6 - A small pump delivers 0.85 gal/h of liquid...Ch. 6 - A small metering pump delivers 11.4 gal of a water...Ch. 6 - A small metering pump delivers 19.5 mL/min of...Ch. 6 - Water at 10 C is flowing at 0.075 m3/s Calculate...Ch. 6 - Oil for a hydraulic system (sg =0.90 ) is flowing...Ch. 6 - A liquid refrigerant (sg = 1.08) is flowing at a...Ch. 6 - After the refrigerant from Problem 6.31 flashes...Ch. 6 - A fan delivers 640ft3/min (CFM) of air. If the...Ch. 6 - A large blower for a furnace delivers 47000ft3/min...Ch. 6 - A furnace requires 1200 Ib/h of air for efficient...Ch. 6 - If a pump removes 1.65 gal/min of water from a...Ch. 6 - Calculate the diameter of a pipe that would carry...Ch. 6 - If the velocity of a liquid is 1.65 ft/s in a...Ch. 6 - When 2000 L/min of water flows through a circular...Ch. 6 - Water flows at 1.20 m/s in a circular section with...Ch. 6 - Figure 6.16 shows a fabricated assembly made from...Ch. 6 - A standard Schedule 40 steel pipe is to be...Ch. 6 - If water at 180 F is flowing with a velocity of...Ch. 6 - A standard steel tube, 1.5 25-mm OD 3 1,5-mm wall...Ch. 6 - The recommended velocity of flow in the discharge...Ch. 6 - Repeat Problem 6.45, except specify suitable sizes...Ch. 6 - Table 6.2 shows the typical volume flow rate for...Ch. 6 - Repeat Problem 6.47 but use Schedule 80 DM pipeCh. 6 - Compute the resulting velocity of flow if 400...Ch. 6 - Repeat Problem 6.49 for a DN 50 Schedule 30 pipe.Ch. 6 - Compute the resulting velocity of flow if 400...Ch. 6 - Repeat Problem 6.51 for a 4-in Schedule 30 pipe.Ch. 6 - From the list of standard hydraulic steel tubing...Ch. 6 - A standard 6-in Schedule 40 steel pipe is carrying...Ch. 6 - For Problems 6.55-6.57, use Fig. 6.3 O to specify...Ch. 6 - For Problems 6.55-6.57, use Fig. 6.3 to specify...Ch. 6 - For Problems 6.55-6.57, use Fig. 6.3 O to specify...Ch. 6 - A venturi meter is a device that uses a...Ch. 6 - A flow nozzle, shown in Fig. 6.18 is used to...Ch. 6 - Gasoline (sg = 0.67) is flowing at 0.11 m3/s in...Ch. 6 - Water at 10 C is flowing from point A to point B...Ch. 6 - Calculate the volume flow rate of water at 5 C...Ch. 6 - Calculate the pressure required in the larger...Ch. 6 - Kerosene with a specific weight of 50.0 lb/ft3 is...Ch. 6 - For the system shown in Fig. 6.23 ; calculate (a)...Ch. 6 - For the system shown in Fig. 6.24ss, calculate (a)...Ch. 6 - For the tank shown in Fig. 6.25lO, calculate the...Ch. 6 - Calculate the pressure of the air in the sealed...Ch. 6 - For the siphon in Fig. 6.26, calculate (a) the...Ch. 6 - For the siphon in Fig. 6.26 , calculate the...Ch. 6 - For the siphon in Fig. 6.26 , assume that the...Ch. 6 - For the siphon shown in Fig. 6.27, calculate (a)...Ch. 6 - For the special fabricated reducer shown in Fig....Ch. 6 - In the fabricated enlargement shown in Fig. 6.29,...Ch. 6 - Figure 6.30 shows a manometer being used to...Ch. 6 - For the venturi meter shown in Fig. 6.30,...Ch. 6 - Oil with a specific weight of 8.64 kN/m3 flows...Ch. 6 - The venturi meter shown in Fig. 6.32 iP carries...Ch. 6 - Oil with a specific gravity of 0.90 is flowing...Ch. 6 - Oil with a specific gravity of 0.90 is flowing...Ch. 6 - Gasoline (sg = 0.67) is flowing at 4.0 ft3/s in...Ch. 6 - Oil with a specific weight of 55.0lb/ft3 flows...Ch. 6 - Draw a plot of elevation head, pressure head,...Ch. 6 - Prob. 6.84PPCh. 6 - Figure 6.36 shows a system in which water flows...Ch. 6 - Figure 6.37 shows a venturi meter with a U-tube...Ch. 6 - For the tank shown in Fig. 6.38, compute the...Ch. 6 - What depth of fluid above the outlet nozzle is...Ch. 6 - Derive Torricelli's theorem for the velocity of...Ch. 6 - Solve Problem 6.88 using the direct application of...Ch. 6 - To what height will the jet of fluid rise for the...Ch. 6 - To what height will the jet of water rise for the...Ch. 6 - What pressure is required above the water in Fig....Ch. 6 - What pressure is required above the water in Fig....Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to empty the tank shown...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Compute the time required to reduce the depth in...Ch. 6 - Prob. 6.103PPCh. 6 - Repeat Problem 6.101 if the tank is sealed and a...Ch. 6 - Repeat Problem 6.96 if the tank is sealed and a...Ch. 6 - Repeat Problem 6.100 if the tank is sealed and a...Ch. 6 - A village currently carries water by hand from a...Ch. 6 - A "spa tub" is to be designed to replace bath tubs...Ch. 6 - A simple soft drink system relies on pressurized...Ch. 6 - A concept team for a toy company is considering a...Ch. 6 - 6.111 Bernoulli's principle applies to Venturi...Ch. 6 - Prob. 6.112PPCh. 6 - You are to develop a mixing valve for use in a...Ch. 6 - Prob. 6.114PPCh. 6 - You would like to empty the in-ground pool in the...Ch. 6 - Prob. 6.116PPCh. 6 - Create a spreadsheet for computing the values of...Ch. 6 - Prob. 2APCh. 6 - Prob. 3APCh. 6 - Create a spreadsheet for computing, using Eq....Ch. 6 - Prob. 5APCh. 6 - Create a spreadsheet for computing the velocity of...
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- For the siphon in the figure below, calculate the SAE 40 oil volume flow rate from the tank, and b) the pressure at points A, B, C, and D.arrow_forwardC2. A conical tube is fixed vertically with its smaller end upwards and it forms a part of the pipeline. The velocity at the smaller end is 4.9 m/s and at the larger end is 2.5 m/s. The length of the conical tube is 1.3 m and the flow rate of the water is 127 liters/s. The pressure at the smaller end is equivalent to a head of 10.1 m of water. Considering the following two cases: (1) Neglecting friction, (without head loss) determine (i) the diameter at the smaller end in meter, (ii) the diameter at the larger end in meter, and (ii) the pressure at the larger end of the tube in m of water. (2) If a head loss (with head loss)in the tube,h = 0.0153(V1-V2)2, where V1 is the velocity at the smaller end and V2 is the velocity at the larger end, determine (iv) the head loss in m of water and (v) the pressure at the larger end of the tube in m of water. 6) the diameter at the smaller end in meter (ii) the diameter at the larger end in meter (iii) the pressure head at the larger end of the…arrow_forwardReview Conceptual Example 6 as an aid in understanding this problem. Consider the pump on the right side of the drawing, which acts to reduce the air pressure in the pipe. The air pressure outside the pipe is one atmosphere. Find the maximum depth from which this pump can extract water from the well.arrow_forward
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