Explanation Given: - Internal diameter of water pipe = 6 in Internal diameter of water outlet = 4 in Water flow rate = 1000 gal/min= 133.681 ft 3 /min = 2.228ft 3 /s Concept used: Pressure at the nozzle inlet should be enough to give an exit velocity head of 50 ft. Q= V× Area Calculation: Q= V×Area outlet Q= 2 .228 ft 3 /s Area outlet = π 4 d 2 = π 4 4 2 = 12 .566in 2 = 0 .0873 ft 2 Q=V×Area outlet 2

7th Edition

ISBN: 9780132558921

Author: Robert L. Mott, Joseph A. Untener

Publisher: PEARSON

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Applied Fluid Mechanics

A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

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Chapter 6, Problem 6.114PP

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Height of water from the fire hydrant.

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Chapter 6, Problem 6.113PP

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Chapter 6 Solutions

Applied Fluid Mechanics (7th Edition)

Ch. 6 - Convert a volume flow rate of 3.0 gal/min to...Ch. 6 - Convert 459 gal/min to rrP/s.Ch. 6 - Convert 3720 gal/min to mJ/s Ch. 6 - Convert 34.3 gal/min to mJ/s Ch. 6 - Convert a volume flow rate of 125 L/min to m3/s.Ch. 6 - Convert 4500 L/min to m5/s.Ch. 6 - Convert 15 000 L/minto m3/s.Ch. 6 - Convert 459 gal/min to L/mnin Ch. 6 - Convert 3720 gal/min to L/min Ch. 6 - Convert 23.5cm2/stom3/s.

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