(a)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The water molecule is formed by the combination of hydrogen and oxygen atoms in 2:1 ratio, the molecular formula of the water is
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
The properties that make water a good solvent are its polarity and its capacity for hydrogen bonding.
The water molecule is polar due to presence of electronegative oxygen and electropositive hydrogen atom, this result in difference in electro-negativities between the atoms in the molecule. This polarity results in good solvent of water as it gives ability to stick to itself, other substances, and have surface tension. The water molecule also forms hydrogen bonding between them due to the presence of oxygen and hydrogen atoms. Due to polarity water forms electrostatic attraction between other polar molecules and ions.
(b)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The compounds formed by the complete transfer of electrons between the atoms is said to be the ionic compound and force of attraction between them is electrostatic force of attraction.
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
When ionic compounds dissolve in water, their ions become solvated by water molecules.
Ionic compounds have atoms which are oppositely charged, known as ions, arranged in such a way to form a lattice. On adding an ionic compound (polar) to water, the ions get attracted to the water molecules as water is also polar in nature. The force of attraction between the ions and water molecule is strong enough to break the bond between the ionic compounds thus, resulting in dissociation of ions and ions gets dispersed in solution by forming the bonds with water (
(c)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The water molecule is formed by the combination of hydrogen and oxygen atoms in 2:1 ratio, the molecular formula of the water is
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
The term “water of hydration” refers to the number of water molecules that surround an ion in aqueous solution.
Water molecule that is chemically combined with a substance to form a hydrate is said to be the water of hydration. The removal of water hydration can be done (either by heating) that do not change the composition of the substance. The hydration generally occurs with secondary minerals.
For example:
(d)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The water molecule is formed by the combination of hydrogen and oxygen atoms in 2:1 ratio, the molecular formula of the water is
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
The term “anhydrous” means “without water”.
The absence of water in a compound is described by the term anhydrous, which means that the structure of compound have no water molecule in it.
(e)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
On dissolving electrolyte (polar in nature) in polar solvents, they get separated into its respective ions that are cations and anions.
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
An electrolyte is a substance that dissolves in water to give a solution that conducts electricity.
An electrolyte is a substance that dissolves in water to give a solution that conducts electricity. On dissolving electrolyte (polar in nature) in polar solvents, they get separated into its respective ions that are cations and anions, which are dispersed uniformly in the solvent. On applying electric potential to such solutions, the ions are drawn to the electrodes due to the abundance and deficiency of electrons on ions thus, resulting in conduction of electricity.
(f)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The formation of ions takes place by the loss or gain of electron. The cation results from the loss of electron whereas the anion results from the gaining of electron by the atom.
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
In a solution that conducts electricity, cations migrate towards the cathode and anions migrate towards the anode.
The loss of electron(s) from the atom results in the formation of cation and the gain of electron(s) by the atom results in the formation of anion. The cathode is negatively charged electrode whereas the positively charged electrode is anode. Since the unlike charges attract so, the cations which are positively charged will move towards negative electrode, cathode whereas the anions which are negatively charged will move towards positive electrode, anode.
(g)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The formation of ions takes place by the loss or gain of electron. The cation results from the loss of electron whereas the anion results from the gaining of electron by the atom.
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
Ions must be present in a solution for the solution to conduct electricity.
On dissolving electrolyte (polar in nature) in polar solvents, they get separated into its respective ions that are cations and anions, which are dispersed uniformly in the solvent. On applying electric potential to such solutions, the ions are drawn to the electrodes due to the abundance and deficiency of electrons on ions thus, resulting in conduction of electricity.
(h)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
The substances that do not dissociate into ions and thus, are non-conductor of electricity are said to be non-electrolytes.
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
Distilled water is a nonelectrolyte.
Water in its pure form does not conduct electricity. The conduction of electricity takes place only due to the presence of ions. In distilled water, there are no such ions present which can conduct electricity thus, distilled water is a nonelectrolyte.
(i)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
A substance that dissolves in water to give a solution that conducts electricity is said to be an electrolyte.
Answer to Problem 6.56P
True.
Explanation of Solution
Given:
A strong electrolyte is a substance that completely dissociates into ions.
An electrolyte is a substance that dissolves in water to give a solution that conducts electricity. On dissolving electrolyte (polar in nature) in polar solvents, they get separated into its respective ions that are cations and anions, which are dispersed uniformly in the solvent. On applying electric potential to such solutions, the ions are drawn to the electrodes due to the abundance and deficiency of electrons on ions thus, resulting in conduction of electricity.
(j)
Interpretation:
To justify whether the given statement is true or false.
Concept Introduction:
A substance that dissolves in water to give a solution that conducts electricity is said to be an electrolyte.
Answer to Problem 6.56P
False.
Explanation of Solution
Given:
All compounds that dissolve in water are electrolytes.
All compounds that dissolve in water do not conduct electricity for example the sugar dissolves in water but the solution does not conduct electricity. Thus, for a solution to conduct electricity the dissociation of ions from the substance should takes place which result in the conduction of electricity.
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Chapter 6 Solutions
Introduction to General, Organic and Biochemistry
- Please correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward(11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)!arrow_forward
- . 3°C with TH 12. (10pts total) Provide the major product for each reaction depicted below. If no reaction occurs write NR. Assume heat dissipation is carefully controlled in the fluorine reaction. 3H 24 total (30) 24 21 2h • 6H total ● 8H total 34 래 Br2 hv major product will be most Substituted 12 hv Br NR I too weak of a participate in P-1 F₂ hv Statistically most favored product will be major = most subst = thermo favored hydrogen atom abstractor to LL Farrow_forwardFive chemistry project topic that does not involve practicalarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Q2. Consider the hydrogenation of ethylene C2H4 + H2 = C2H6 The heats of combustion and molar entropies for the three gases at 298 K are given by: C2H4 C2H6 H2 AH comb/kJ mol¹ -1395 -1550 -243 Sº / J K¹ mol-1 220.7 230.4 131.1 The average heat capacity change, ACP, for the reaction over the temperature range 298-1000 K is 10.9 J K¹ mol¹. Using these data, determine: (a) the standard enthalpy change at 800 K (b) the standard entropy change at 800 K (c) the equilibrium constant at 800 K.arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)! Googlearrow_forwardPrint Last Name, First Name Initial Statifically more chances to abstract one of these 6H 11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4 4th total • 6H total 래 • 4H total 21 total ZH 2H Statistical H < 3° C-H weakest - product abstraction here bund leads to thermo favored a) (6pts) How many unique mono-chlorinated products can be formed and what are the structures for the thermodynamically and statistically favored products? Product 6 Number of Unique Mono-Chlorinated Products Thermodynamically Favored Product Statistically Favored Product b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the formation of the thermodynamically favored product. Only draw the p-1 step. You do not need to include lone pairs of electrons. No enthalpy calculation necessary H H-Cl Waterfoxarrow_forward
- 10. (5pts) Provide the complete arrow pushing mechanism for the chemical transformation → depicted below Use proper curved arrow notation that explicitly illustrates all bonds being broken, and all bonds formed in the transformation. Also, be sure to include all lone pairs and formal charges on all atoms involved in the flow of electrons. CH3O II HA H CH3O-H H ①arrow_forwardDo the Lone Pairs get added bc its valence e's are a total of 6 for oxygen and that completes it or due to other reasons. How do we know the particular indication of such.arrow_forwardNGLISH b) Identify the bonds present in the molecule drawn (s) above. (break) State the function of the following equipments found in laboratory. Omka) a) Gas mask b) Fire extinguisher c) Safety glasses 4. 60cm³ of oxygen gas diffused through a porous hole in 50 seconds. How long w 80cm³ of sulphur(IV) oxide to diffuse through the same hole under the same conditions (S-32.0.0-16.0) (3 m 5. In an experiment, a piece of magnesium ribbon was cleaned with steel w clean magnesium ribbon was placed in a crucible and completely burnt in oxy cooling the product weighed 4.0g a) Explain why it is necessary to clean magnesium ribbon. Masterclass Holiday assignmen PB 2arrow_forward
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