Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN: 9781285869759
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
Question
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Chapter 6, Problem 6.34P
Interpretation Introduction

(a)

Interpretation:

The formation of following solutions should be explained:

500.0 mL of a 5.32 % w/w H2S solution in water.

Concept Introduction:

Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In mass of solute per unit mass of solvent, or w/w, the total mass of the solute, solvent and solution must be known.

The formula for w/w is as follows:

Cw/w=msoluteMsolvent×100%.

Here, msolute is mass of solute and msolvent is mass of solvent.

When solving for the required amount of solute, the following formula is used:

Cw/w=msolutemsolute+Msolvent×100%.

Expert Solution
Check Mark

Answer to Problem 6.34P

28.09 g of the solute must be added.

Explanation of Solution

Given Information:

V=500.0 mLC=5.32 %w/w.

The concentration is shown as w/w meaning this is mass of solute per mass of solvent.

Since, density of water is 1 g/mL thus, 500 mL of water contains 500 g of water. Substitute known data and solve for mass of solute.

5.32%=msolutemsolute+500.0 g×100%5.32%100%=msolutemsolute+500.0 g0.0532(msolute+500.0 g)=msolute0.0532(msolute)+26.6 g=msolute(10.0532)(msolute)=26.6 gmsolute=26.6 g0.9468=28.09 g.

Thus, 28.09 g of solute is added to the total 500.0 mL of solvent in order to get a 5.32% of w/w solution.

(b)

Interpretation Introduction

Interpretation:

The formation of following solutions should be explained:

342.0 mL of a 0.443 % w/w benzene solution in toluene.

Concept Introduction:

Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In mass of solute per unit mass of solvent, or w/w, the total mass of the solute, solvent and solution must be known.

The formula for w/w is as follows:

Cw/w=msoluteMsolvent×100%.

Here, msolute is mass of solute and msolvent is mass of solvent.

When solving for the required amount of solute, the following formula is used:

Cw/w=msolutemsolute+Msolvent×100%.

(b)

Expert Solution
Check Mark

Answer to Problem 6.34P

1.515 mL of the solute must be added.

Explanation of Solution

Given Information:

V=342 mLC=0.443%w/wDtoluene=0.867 g/mLDbenzene=0.876  g/mL.

The concentration is shown as w/w meaning this is mass of solute per mass of solvent.

In this specific case, we do not know which volume or mass each material is, but we do know which one the solvent is, toluene.

Masstotal=Massbenzene+MasstolueneMasstotal=DbenzeneVbenzene+DtolueneVtolueneCw/w=msolutemsolute+msolvent×100%0.443%=DbenzeneVbenzeneDbenzeneVbenzene+DtolueneVtoluene×100%0.443%=0.876gmL(Vbenzene)0.876gmL(Vbenzene)+0.867gmLX(Vtoluene)×100%.

Now, get the total volume equation.

Vtotal=Vbenzene+Vtoluene342.00 mL=Vbenzene+VtolueneVtoluene=342.00 mLVbenzene.

Solve simultaneously.

0.443%=0.876gmL(Vbenzene)0.876gmL(Vbenzene)+0.867gmLX(Vtoluene)×100%Vtoluene=342.00 mLVbenzene0.443%=0.876gmL(Vbenzene)0.876gmL(Vbenzene)+0.867gmL(342.00 mLVbenzene)×100%0.443%100%=0.876gmL(Vbenzene)0.876gml(Vbenzene)+0.867gmL(342.00 mLVbenzene)0.876×Vbenzene0.00443=0.876×Vbenzene+296.50.867×Vbenzene195.7Vbenzene=0.876×Vbenzene+296.50.867×VbenzeneVbenzene(195.70.876+0.867)=296.5Vbenzene=296.5195.691Vbenzene=1.515 mL.

Then, add 1.515 mL to the mixture. Add all remaining volume of toluene:

Vtoluene=342.00mlVbenzeneVtoluene=3421.515=340.485 mL.

Interpretation Introduction

(c)

Interpretation:

The formation of following solutions should be explained:

125.5 mL of a 34.2 % w/w dimethyl sulfoxide solution in acetone.

Concept Introduction:

Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In mass of solute per unit mass of solvent, or w/w, the total mass of the solute, solvent and solution must be known.

The formula for w/w is as follows:

Cw/w=msoluteMsolvent×100%.

Here, msolute is mass of solute and msolvent is mass of solvent.

When solving for the required amount of solute, the following formula is used:

Cw/w=msolutemsolute+Msolvent×100%.

Expert Solution
Check Mark

Answer to Problem 6.34P

VDMS=3.379 mL of the solute must be added.

Explanation of Solution

Given:

V=12.5mlC=34.2%w/wDdimethylsulfoxide=1.1004 g/mlDaCetOne=0.784  g/ml.

In this specific case, we do not know which volume or mass each material is, but we do know which one is the solvent that is acetone.

Masstotal=Massbenzene+MasstolueneMasstotal=DbenzeneVbenzene+DtolueneVtoluene34.2%=msolutemsolute+msolvent×100%34.2%=DMDSVMDSDMDSVMDS+DAcetoneVAcetone×100%34.2%=1.1004×VMDS1.1004×VMDS+0.784gmL×(VAcetone)×100%.

Now, get the total volume equation.

Vtotal=VDMS+VAcetone12.5 mL=VDMS+VAcetoneVacetone=12.5 mlVDMS.

Solve simultaneously.

34.2%=0.876gmL(VDMS)0.876gml(VDMS)+0.867gmlX(342.00mlVDMS)×100%34.2100%=1.1×VDMS1.1gml(VDMS)+0.784gml×(12.5mlVDMS)1.1×VDMS0.342=1.1VDMS+9.80.784VDMS(3.2161.1+0.784)VDMS=9.8 mLVDMS=9.82.9VDMS=3.379 mL.

Then, add VDMS=3.379ml to the mixture. Add all remaining volume of acetone:

V=12.5 mL3.379 mLVaCetOne=9.121 mL.

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Chapter 6 Solutions

Introduction to General, Organic and Biochemistry

Ch. 6.8 - Prob. 6.11PCh. 6.8 - Prob. 6.12PCh. 6.8 - Problem 6-13 What is the osmolarity of a 3.3% w/v...Ch. 6.8 - Prob. 6.14PCh. 6 - 6-15 Answer true or false. (a) A solute is the...Ch. 6 - 6-16 Answer true or false. (a) Solubility is a...Ch. 6 - 6-17 Vinegar is a homogeneous aqueous solution...Ch. 6 - 6-18 Suppose you prepare a solution by dissolving...Ch. 6 - 6-19 In each of the following, tell whether the...Ch. 6 - 6-20 Give a familiar example of solutions of each...Ch. 6 - 6-21 Are mixtures of gases true solutions or...Ch. 6 - 6-22 Answer true or false. (a) Water is a good...Ch. 6 - 6-23 We dissolved 0.32 g of aspartic acid in 115.0...Ch. 6 - Prob. 6.24PCh. 6 - 6-25 A small amount of solid is added to a...Ch. 6 - 6-26 On the basis of polarity and hydrogen...Ch. 6 - Prob. 6.27PCh. 6 - 6-28 Which pairs of liquids are likely to be...Ch. 6 - Prob. 6.29PCh. 6 - 6-30 Near a power plant, warm water is discharged...Ch. 6 - 6-31 If a bottle of beer is allowed to stand for...Ch. 6 - 6-32 Would you expect the solubility of ammonia...Ch. 6 - Prob. 6.33PCh. 6 - Prob. 6.34PCh. 6 - 6-35 Describe how we would prepare the following...Ch. 6 - Prob. 6.36PCh. 6 - 6-37 Calculate the w/v percentage of each of these...Ch. 6 - 6-38 Describe how we would prepare 250 mL of 0.10...Ch. 6 - 6-39 Assuming that the appropriate volumetric...Ch. 6 - 6-40 What is the molarity of each solution? (a) 47...Ch. 6 - 6-41 A teardrop with a volume of 0.5 mL contains...Ch. 6 - Prob. 6.42PCh. 6 - 6-43 The label on a sparkling cider says it...Ch. 6 - Prob. 6.44PCh. 6 - 6-45 The label on ajar of jam says it contains 13...Ch. 6 - 6-46 A particular toothpaste contains 0.17 g NaF...Ch. 6 - 6-47 A student has a bottle labeled 0.750% albumin...Ch. 6 - 6-48 How many grams of solute are present in each...Ch. 6 - 6-49 A student has a stock solution of 30.0% w/v...Ch. 6 - Prob. 6.50PCh. 6 - Prob. 6.51PCh. 6 - Prob. 6.52PCh. 6 - 6-53 Dioxin is considered to be poisonous in...Ch. 6 - 6-54 An industrial wastewater contains 3.60 ppb...Ch. 6 - 6-55 According to the label on a piece of cheese,...Ch. 6 - Prob. 6.56PCh. 6 - Prob. 6.57PCh. 6 - Prob. 6.58PCh. 6 - Prob. 6.59PCh. 6 - 6-60 Predict which of these covalent compounds is...Ch. 6 - Prob. 6.61PCh. 6 - Prob. 6.62PCh. 6 - Prob. 6.63PCh. 6 - Prob. 6.64PCh. 6 - Prob. 6.65PCh. 6 - 6-66 What gives nanotubes their unique optical and...Ch. 6 - 6-67 Calculate the freezing points of solutions...Ch. 6 - 6-68 If we add 175 g of ethylene glycol, C2H6O2,...Ch. 6 - Prob. 6.69PCh. 6 - 6-70 In winter, after a snowstorm, salt (NaCI) is...Ch. 6 - 6-71 A 4 M acetic acid (CH3COOH) solution lowers...Ch. 6 - Prob. 6.72PCh. 6 - 6-73 In each case, tell which side (if either)...Ch. 6 - 6-74 An osmotic semipermeable membrane that allows...Ch. 6 - 6-75 Calculate the osmolarity of each of the...Ch. 6 - Prob. 6.76PCh. 6 - Prob. 6.77PCh. 6 - 6-78 (Chemical Connections 6A) Oxides of nitrogen...Ch. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - 6-82 (Chemical Connections 6C) A solution contains...Ch. 6 - 6-83 (Chemical Connections 6C) The concentration...Ch. 6 - 6-84 (Chemical Connections 6D) What is the...Ch. 6 - Prob. 6.85PCh. 6 - Prob. 6.86PCh. 6 - Prob. 6.87PCh. 6 - Prob. 6.88PCh. 6 - Prob. 6.89PCh. 6 - Prob. 6.90PCh. 6 - 6-91 When a cucumber is put into a saline solution...Ch. 6 - Prob. 6.92PCh. 6 - 6-93 Two bottles of water are carbonated, with CO2...Ch. 6 - Prob. 6.94PCh. 6 - Prob. 6.95PCh. 6 - 6-96 We know that a 0.89% saline (NaCI) solution...Ch. 6 - Prob. 6.97PCh. 6 - Prob. 6.98PCh. 6 - 6-99 A concentrated nitric acid solution contains...Ch. 6 - 6-100 Which will have greater osmotic pressure?...Ch. 6 - Prob. 6.101PCh. 6 - Prob. 6.102PCh. 6 - 6-103 A swimming pool containing 20,000. L of...Ch. 6 - Prob. 6.104PCh. 6 - Prob. 6.105PCh. 6 - Prob. 6.106PCh. 6 - Prob. 6.107PCh. 6 - Prob. 6.108PCh. 6 - Prob. 6.109PCh. 6 - Prob. 6.110PCh. 6 - 6-111 As noted in Section 6-8C, the amount of...Ch. 6 - 6-112 List the following aqueous solutions in...Ch. 6 - 6-113 List the following aqueous solutions in...
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