Explanation Given information: The total available pumping power is equal to 8000 h p The total length is 2147 m i l e s The power of the pump can be defined as below, P o w e r = ρ g Q h f In above equation, ρ - Density of the fluid Q - Volumetric flow rate h p - Head loss The head loss is defined as, h f = V 2 2 g ( f L D ) In above equation, V - Velocity of the flow f - Friction factor L - Length D - Diameter Assume, that the crude oil at 40 ° C will have, ρ = 1.67 s l u g / f t 3 μ = 1.11 × 10 − 4 s l u g / ( f t . s ) Calculation: Convert, 8000 h p = 4400000 l b f . f t / s 2147 m i l e s = 1.1336 × 10 7 f t To find the flow rate, P = ρ g Q h f Substitute for head loss, P = ρ Q V 2 2 ( f L D ) Assume, f = 0.015 In above equation, substitute for flow rate, P = ρ π D V 3 8 ( f L ) Find the velocity from above equation, P = ρ π D V 3 8 ( f L ) 4400000 l b f . f t / s = π ( 1.67 s l u g / f t 3 ) ( 3 f t ) V 3 8 ( 0.015 ) ( 1.1336 × 10 7 f t ) V = 2.36 f t / s Find the Reynolds’s number, Re = ρ V D μ = ( 1.67 s l u g / f t 3 ) ( 2

8th Edition

ISBN: 9789385965494

Author: Frank White

Publisher: MCGRAW-HILL HIGHER EDUCATION

See similar textbooks

Question

Chapter 6, Problem 6.48P

To determine

The flow rate in barrels per minute.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 6, Problem 6.47P

Chapter 6, Problem 6.49P

Students have asked these similar questions

The T-shaped structure is embedded in a concrete wall at A and subjected to the force F₁ and the force-couple system F2 1650 N and M = 1,800 N-m at the locations shown. Neglect the weight of the structure in your calculations for this problem. = a.) Compute the allowable range of magnitudes for F₁ in the direction shown if the connection at A will fail when subjected to a resultant moment with a magnitude of 920 N- m or higher. b.) Focusing on the forces and igonoring given M for now. Using the value for F1, min that you calculated in (a), replace the two forces F₁ and F2 with a single force that has equivalent effect on the structure. Specify the equivalent →> force Feq in Cartesian components and indicate the horizontal distance from point A to its line of action (note this line of action may not intersect the structure). c.) Now, model the entire force system (F1,min, F2, and M) as a single force and couple acting at the junction of the horizontal and vertical sections of the…

The heated rod from Problem 3 is subject to a volumetric heating h(x) = h0 x L in units of [Wm−3], as shown in the figure below. Under the heat supply the temperature of the rod changes along x with the temperature function T (x). The temperature T (x) is governed by the d following equations: − dx (q(x)) + h(x) = 0 PDE q(x) =−k dT dx Fourier’s law of heat conduction (4) where q(x) is the heat flux through the rod and k is the (constant) thermal conductivity. Both ends of the bar are in contact with a heat reservoir at zero temperature. Determine: 1. Appropriate BCs for this physical problem. 2. The temperature function T (x). 3. The heat flux function q(x). Side Note: Please see that both ends of bar are in contact with a heat reservoir at zero temperature so the boundary condition at the right cannot be du/dx=0 because its not thermally insulated. Thank you

The elastic bar from Problem 1 spins with angular velocity ω about an axis, as shown in the figure below. The radial acceleration at a generic point x along the bar is a(x) = ω2x. Under this radial acceleration, the bar stretches along x with displacement function u(x). The displacement d u(x) is governed by the following equations: dx (σ(x)) + ρa(x) = 0 PDE σ(x) = E du dx Hooke’s law (2) where σ(x) is the axial stress in the rod, ρ is the mass density, and E is the (constant) Young’s modulus. The bar is pinned on the rotation axis at x = 0 and it is also pinned at x = L. Determine: 1. Appropriate BCs for this physical problem. 2. The displacement function u(x). 3. The stress function σ(x). SIDE QUESTION: I saw a tutor solve it before but I didn't understand why the tutor did not divide E under the second term (c1x) before finding u(x). The tutor only divided E under first term. please explain and thank you

Chapter 6 Solutions

Fluid Mechanics, 8 Ed

Ch. 6 - Prob. 6.1P Ch. 6 - The present pumping rate of crude oil through the...Ch. 6 - The Keystone Pipeline in the chapter opener photo...Ch. 6 - For flow of SAE 30 oil through a 5-cm-diameter...Ch. 6 - In flow past a body or wall, early transition to...Ch. 6 - P6.6 For flow of a uniform stream parallel to a...Ch. 6 - SAE 10W30 oil at 20°C flows from a tank into a...Ch. 6 - P6.8 When water at 20°C is in steady turbulent...Ch. 6 - A light liquid 950kg/m3 flows at an average...Ch. 6 - Water at 20°C flows through an inclined...

Knowledge Booster