Explanation Given Information: The figure is given as, Temperature at which the water flows = 20 o C Tube through which water flows = 1 m long and 2 mm dia Water flow height = 50 cm From point 1 and 2, using the Bernoulli’s equation, we get, At point 1 and 2, p 1 ρ g + V 1 2 2 g + z 1 = p 2 ρ g + V 2 2 2 g + z 2 + h f Where, At point 1, p 1 ρ g = pressure force V 1 2 2 g = kinetic energy z 1 = potential energy At point 2, p 2 ρ g = pressure force V 2 2 2 g = kinetic energy z 2 = potential energy h f = energy loss of friction At point 1, the flow of kinetic energy is 0, so V 1 = 0, and the pressure is atmospheric at point 1 and 2, therefore, we get, z 1 = V 2 2 g + z 2 + h f z 1 − z 2 − V 2 2 g = h f h f = H − V 2 2 g [ ∵ z 1 − z 2 = H ] The flow is laminar, 32 μ V L ρ g d 2 = H − V 2 2 g [ ∵ h f = 32 μ V L ρ g d 2 ] Substituting the values, H = 0

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ISBN: 9789385965494

Author: Frank White

Publisher: MCGRAW-HILL HIGHER EDUCATION

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Chapter 6, Problem 6.14P

To determine

The height H and the flow rate.

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Chapter 6 Solutions

Fluid Mechanics, 8 Ed

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