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L 1) Using your Blueprint reading and Math Skills from this term, Determine the Angle of Rotation, and Angle of Tilt of the Drilled hole. 0.5 3.5 3.5 Next Unit md 2 April Tan (

L 1) Using your Blueprint reading and Math Skills from this term, Determine the Angle of Rotation, and Angle of Tilt of the Drilled hole. 0.5 3.5 3.5 Next Unit md 2 April Tan (

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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This is a tilt and rotation question. Here are notes attached for reference. I prefer handwritten solutions. ONLY UPLOAD A SOLUTION IF YOU ARE SURE ABOUT THE ANSWER PLEASE. I prefer handwritten solutions.(If you had once answered this question don't answer it as I am looking for a different solution)

L 1) Using your Blueprint reading and Math Skills from this term, Determine the Angle of Rotation, and Angle of Tilt of the Drilled hole. 0.5 3.5 3.5
Transcribed Image Text:L 1) Using your Blueprint reading and Math Skills from this term, Determine the Angle of Rotation, and Angle of Tilt of the Drilled hole. 0.5 3.5 3.5
Next Unit md 2 April Tan (<CAB) = (8) Tan (CCAB) = opp opp まる adj Compute Diagonal Lengths and Angle Sizes in Rectangular Solids 5 50 २० 2 Tan ( 0 ) = 2.5 =Tan (2.5) <CAB = 68... 10 111·4.02 90270 ABAC²+CB AB² = 15² + 114.02² AB²=5625+12446 JAB U18621 8100 Tan (c)= opp adj Tan (CR) = 80 Too = 80²+10 | AB = 50 41 28.05² 2 =6400+ 1000co AB = 2500+1894.36 = 16400 =V16900 = 128.06 cm AB = 13747 Tan(CT)=12106 "Tan (CR) = 0.8 109 1103 CR Tan Co. CR = 38.65 50 CT-68.67% 70 CB-90²+702 Co²-11074900 90 CB²=13800 CB= 114.02 Tam (CA)=70 ५० 90 CR-37.17 A 13646B tan (<T) = 114.02 114.02 Tan (CA)=70 <R=37.87° CT = 56.65° AB=136.46
Transcribed Image Text:Next Unit md 2 April Tan (<CAB) = (8) Tan (CCAB) = opp opp まる adj Compute Diagonal Lengths and Angle Sizes in Rectangular Solids 5 50 २० 2 Tan ( 0 ) = 2.5 =Tan (2.5) <CAB = 68... 10 111·4.02 90270 ABAC²+CB AB² = 15² + 114.02² AB²=5625+12446 JAB U18621 8100 Tan (c)= opp adj Tan (CR) = 80 Too = 80²+10 | AB = 50 41 28.05² 2 =6400+ 1000co AB = 2500+1894.36 = 16400 =V16900 = 128.06 cm AB = 13747 Tan(CT)=12106 "Tan (CR) = 0.8 109 1103 CR Tan Co. CR = 38.65 50 CT-68.67% 70 CB-90²+702 Co²-11074900 90 CB²=13800 CB= 114.02 Tam (CA)=70 ५० 90 CR-37.17 A 13646B tan (<T) = 114.02 114.02 Tan (CA)=70 <R=37.87° CT = 56.65° AB=136.46
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