elements, each with a length of 1 m. Determine the temperature on node 1, 2, 3, 4. 3. Solve the strong form analytically (you may choose Maple, MATLAB or Mathematica to help you solve this ODE). Compare the FE approximate temperature distribution through the block against the analytical solution. 1 (1) 200 °C 2 (2) 3 m 3 (3) 9₁ A Insulated boundary Insulated boundary dx Let's begin with the strong form for a steady-state one-dimensional heat conduction problem, without convection. d dT + Q = dx dx According to Fourier's law of heat conduction, the heat flux q(x), is dT q(x)=-k dx. x Q is the internal heat source, which heat is generated per unit time per unit volume. q(x) and q(x + dx) are the heat flux conducted into the control volume at x and x + dx, respectively. k is thermal conductivity along the x direction, A is the cross-section area perpendicular to heat flux q(x). T is the temperature, and is the temperature gradient. dT dx 1. Derive the weak form using w(x) as the weight function. 2. Consider the following scenario: a 1D block is 3 m long (L = 3 m), with constant cross-section area A = 1 m². The left free surface of the block (x = 0) is maintained at a constant temperature of 200 °C, and the right surface (x = L = 3m) is insulated. Recall that Neumann boundary conditions are naturally satisfied in the weak form, for x = 3 m, use q = 0 to simplify boundary terms. The thermal conductivity is k = 25 W/(m. °C). There is a uniform generation of heat inside the block which is Q = 100 W/m³. Using weak form Galerkin's method, approximate T(x) with linear shape functions N₁(x). Use three
elements, each with a length of 1 m. Determine the temperature on node 1, 2, 3, 4. 3. Solve the strong form analytically (you may choose Maple, MATLAB or Mathematica to help you solve this ODE). Compare the FE approximate temperature distribution through the block against the analytical solution. 1 (1) 200 °C 2 (2) 3 m 3 (3) 9₁ A Insulated boundary Insulated boundary dx Let's begin with the strong form for a steady-state one-dimensional heat conduction problem, without convection. d dT + Q = dx dx According to Fourier's law of heat conduction, the heat flux q(x), is dT q(x)=-k dx. x Q is the internal heat source, which heat is generated per unit time per unit volume. q(x) and q(x + dx) are the heat flux conducted into the control volume at x and x + dx, respectively. k is thermal conductivity along the x direction, A is the cross-section area perpendicular to heat flux q(x). T is the temperature, and is the temperature gradient. dT dx 1. Derive the weak form using w(x) as the weight function. 2. Consider the following scenario: a 1D block is 3 m long (L = 3 m), with constant cross-section area A = 1 m². The left free surface of the block (x = 0) is maintained at a constant temperature of 200 °C, and the right surface (x = L = 3m) is insulated. Recall that Neumann boundary conditions are naturally satisfied in the weak form, for x = 3 m, use q = 0 to simplify boundary terms. The thermal conductivity is k = 25 W/(m. °C). There is a uniform generation of heat inside the block which is Q = 100 W/m³. Using weak form Galerkin's method, approximate T(x) with linear shape functions N₁(x). Use three
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter5: Analysis Of Convection Heat Transfer
Section: Chapter Questions
Problem 5.17P
Related questions
Question
Transcribed Image Text:elements, each with a length of 1 m. Determine the temperature on
node 1, 2, 3, 4.
3. Solve the strong form analytically (you may choose Maple, MATLAB
or Mathematica to help you solve this ODE). Compare the FE
approximate temperature distribution through the block against the
analytical solution.
1
(1)
200 °C
2
(2)
3 m
3
(3)
Transcribed Image Text:9₁
A
Insulated boundary
Insulated boundary
dx
Let's begin with the strong form for a steady-state one-dimensional heat
conduction problem, without convection.
d dT
+ Q =
dx dx
According to Fourier's law of heat conduction, the heat flux q(x), is
dT
q(x)=-k
dx. x
Q is the internal heat source, which heat is generated per unit time per unit
volume. q(x) and q(x + dx) are the heat flux conducted into the control
volume at x and x + dx, respectively. k is thermal conductivity along the x
direction, A is the cross-section area perpendicular to heat flux q(x). T is the
temperature, and is the temperature gradient.
dT
dx
1. Derive the weak form using w(x) as the weight function.
2. Consider the following scenario: a 1D block is 3 m long (L = 3 m), with
constant cross-section area A = 1 m². The left free surface of the block
(x = 0) is maintained at a constant temperature of 200 °C, and the right
surface (x = L = 3m) is insulated. Recall that Neumann boundary
conditions are naturally satisfied in the weak form, for x = 3 m, use
q = 0 to simplify boundary terms. The thermal conductivity is k =
25 W/(m. °C). There is a uniform generation of heat inside the block
which is Q = 100 W/m³. Using weak form Galerkin's method,
approximate T(x) with linear shape functions N₁(x). Use three
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 3 images
Recommended textbooks for you
Principles of Heat Transfer (Activate Learning wi…
Mechanical Engineering
ISBN:
9781305387102
Author:
Kreith, Frank; Manglik, Raj M.
Publisher:
Cengage Learning
Principles of Heat Transfer (Activate Learning wi…
Mechanical Engineering
ISBN:
9781305387102
Author:
Kreith, Frank; Manglik, Raj M.
Publisher:
Cengage Learning