4. Determine the support reactions at point A and B. A 100 lb/ft 300 lb B 4' — 4' → 2' 2'
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- 5) Use the method of sections to find the true magnitude and direction in bar DB of the truss. Hint( Joint C is in equilibrium) В 45° F. 4' E 4' -100 Ibs1.500 N/m 0750m 1.500m 275 AN 2.25 1.500m Refer to the diagram. ACD is a rigid member. Determine the magnitude of the reaction at the pint C, = kN. Determine the magnitude of the x-component of the reaction at A, Ax = N. Determine the magnitude of the y-component of the reaction at A. Ay = kN. Determine the magnitude of the resultant of the reaction at A, FA= kN.Find the reactions at the support
- 4. Determine the reactions at points of contact A, B, and C needed to support the force of 800 N. Neglect the thickness of the smooth pipe in the calculation. A 0.26 m 30 0.5 m 0.5m 30 0.15 m 800 NFind the external reactions of the Fixed Support at A.a) As shown in the image given, a 69-kg crate is supported at equilibrium. The angles alpha=112 degrees. beta=145 degrees and the V =64.3 degrees. The coordinates of point D are (-2.2, 5.6, 3.2)m, and the spring constant k=1170N/m. Determine the stretch in the spring, in m which must be rounded to 3 places after the decimal point. Take g=9.81m/s^2. b) As shown in the image given, a 63-kg crate is supported at equilibrium. The angles alpha=112 degrees. beta=145 degrees and the V =64.3 degrees. The coordinates of point D are (-2.4, 5.5, 3.7)m. Determine the tension force in cable AC, in N. Take g=9.81m/s^2. c) As shown in the image given, a 64-kg crate is supported at equilibrium. The angles alpha=112 degrees. beta=145 degrees and the V =64.3 degrees. The coordinates of point D are (-2.2, 5.4, 3.2)m. Determine the tension force in cable AD, in N. Take g=9.81m/s^2.

