Sulfur trioxide (SO3) dissolves in and reacts with water to form an aqueous solution of sulfuric acid (H2SO4). The vapor in equilibrium with the solution contains both SO3 and H2O. If enough SO3 is added, all of the water reacts and the solution becomes pure H2SO4. If still more SO3 is added, it dissolves to form a solution of SO3 in H3SO4, called oleum or fuming sulfuric acid. The vapor in equilibrium with oleum is pure SO3. Twenty percent oleum by de?nition contains 20 kg of dissolved SO3 and 80 kg of H2SO4 per hundred kilograms of solution. Alliteratively, the oleum composition can be expressed as % SO3 by mass, with the constituents of the oleum considered to be SO3 and H2O.
(a) Prove that a 15.0% oleum contains 84.4% SO3.
(b) Suppose a gas stream at 40°C and 1.2 atm containing 90 mole% SO3 and 10% N2 contacts a liquid stream of 98 wt% H2SO4 (aq), producing 15% oleum. Tabulated equilibrium data indicate that the partial pressure of SO3 in equilibrium with this oleum is 1.15 mm Hg. Calculate (i) the mole fraction of SO3 in the outlet gas if this gas is in equilibrium with the liquid product at 40°C and 1 atm, and (ii) the ratio (m3 gas feed)/(kg liquid feed).
Want to see the full answer?
Check out a sample textbook solutionChapter 6 Solutions
ELEM.PRIN.OF CHEMICAL...ABRIDGED (LL)
Additional Engineering Textbook Solutions
Starting Out with Python (4th Edition)
Electric Circuits. (11th Edition)
Starting Out With Visual Basic (8th Edition)
Degarmo's Materials And Processes In Manufacturing
Introduction To Programming Using Visual Basic (11th Edition)
INTERNATIONAL EDITION---Engineering Mechanics: Statics, 14th edition (SI unit)
- Ex. HW. A vertical glass tube, 2cm ID & 5m long in heated uniformly over its length. The water enter at (200-204 C) & 68.9 bar calculated the pressure drop if the flowrate 0.15 Kg/s & the power applied as a heat to the fluid is 100KW using the homogeneous model. Given that enthalpy at inlet temp.=0.87MJ/Kg, enthalpy saturation temp (285C)=1.26 MJ/Kg and μl=0.972*10-4 Ns/m2, μG=2.89*10-5 Ns/m2, UG=2.515*10-2m3/Kg and the change in UG over range of pressure=-4.45*10-4m3/Kg/bar.arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forwardand the viscosity of the water is 1.24 × 104 Nsm 2. Answer: Slug flow 1. Determine the range of mean density of a mixture of air in a 50:50 oil-water liquid phase across a range of gas void fractions. The den- sity of oil is 900 kgm³, water is 1000 kgm³, and gas is 10 kgm³.arrow_forward
- A chemical reaction takes place in a container of cross-sectional area 50.0 cm2. As a result of the reaction, a piston is pushed out through 15 cm against an external pressure of 121 kPa. Calculate the work done (in J) by the system.arrow_forwardExample 7.2 Steam is generated in a high pressure boiler containing tubes 2.5 m long and 12.5 mm internal diameter. The wall roughness is 0.005 mm. Water enters the tubes at a pressure of 55.05 bar and a temperature of 270°C, and the water flow rate through each tube is 500 kg/h. Each tube is heated uniformly at a rate of 50 kW. Calle (a) Estimate the pressure drop across each tube (neglecting end effects) using (i) the homogeneous flow model and (ii) the Martinelli-Nelson correlation. (b) How should the calculation be modified if the inlet temperature were 230°C at the same pressure?arrow_forwardPlease solve this question by simulation in aspen hysysarrow_forward
- (11.35. For a binary gas mixture described by Eqs. (3.37) and (11.58), prove that: 4812 Pу132 ✓ GE = 812 Py1 y2. ✓ SE dT HE-12 T L = = (812 - 7 1/8/123) d² 812 Pylyz C=-T Pylyz dT dT² See also Eq. (11.84), and note that 812 = 2B12 B11 - B22. perimental values of HE for binary liquid mixtures ofarrow_forwardplease provide me the solution with more details. because the previous solution is not cleararrow_forwardplease, provide me the solution with details.arrow_forward
- Introduction to Chemical Engineering Thermodynami...Chemical EngineeringISBN:9781259696527Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark SwihartPublisher:McGraw-Hill EducationElementary Principles of Chemical Processes, Bind...Chemical EngineeringISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEYElements of Chemical Reaction Engineering (5th Ed...Chemical EngineeringISBN:9780133887518Author:H. Scott FoglerPublisher:Prentice Hall
- Industrial Plastics: Theory and ApplicationsChemical EngineeringISBN:9781285061238Author:Lokensgard, ErikPublisher:Delmar Cengage LearningUnit Operations of Chemical EngineeringChemical EngineeringISBN:9780072848236Author:Warren McCabe, Julian C. Smith, Peter HarriottPublisher:McGraw-Hill Companies, The