Question: McDaniel Shipyards wants to develop control charts to assess the quality of its steel plate. They take ten sheets of 1" steel plate and compute the number of cosmetic flaws on eac... McDaniel Shipyards wants to develop control charts to assess the quality of its steel plate. They take ten sheets of 1" steel plate and compute the number of cosmetic flaws on each roll. Each sheet is 20' by 100'. Based on the following data, develop limits for the control chart, plot the control chart, and determine whether the process is in control. Answer the following questions below. Number of flaws Sheet 1 1 2 1 = 3 2 4 0 5 1 6 5 7 0 8 2 9 10 0 2 PLEASE WRTIE NEATLY AND EXPLAIN! (: Thanks 1. Calculate the standard deviation of control chart. (a) the standard deviation = 1.0832 (b) the standard deviation = 1.1832 (c) the standard deviation = 1.4 (d) the standard deviation = 1.04 27. 2. Using +- 3 olimits, calculate the LCL and UCL for these data. 3.549; LCL = -3.549 (a) UCL (b) UCL 3.549; LCL = 0 ( c) UCL 1.4; LCL = -1.4 (d) UCL 1.4; LCL = 0 (e) UCL 4.949; LCL = 0
Question: McDaniel Shipyards wants to develop control charts to assess the quality of its steel plate. They take ten sheets of 1" steel plate and compute the number of cosmetic flaws on eac... McDaniel Shipyards wants to develop control charts to assess the quality of its steel plate. They take ten sheets of 1" steel plate and compute the number of cosmetic flaws on each roll. Each sheet is 20' by 100'. Based on the following data, develop limits for the control chart, plot the control chart, and determine whether the process is in control. Answer the following questions below. Number of flaws Sheet 1 1 2 1 = 3 2 4 0 5 1 6 5 7 0 8 2 9 10 0 2 PLEASE WRTIE NEATLY AND EXPLAIN! (: Thanks 1. Calculate the standard deviation of control chart. (a) the standard deviation = 1.0832 (b) the standard deviation = 1.1832 (c) the standard deviation = 1.4 (d) the standard deviation = 1.04 27. 2. Using +- 3 olimits, calculate the LCL and UCL for these data. 3.549; LCL = -3.549 (a) UCL (b) UCL 3.549; LCL = 0 ( c) UCL 1.4; LCL = -1.4 (d) UCL 1.4; LCL = 0 (e) UCL 4.949; LCL = 0
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Question: McDaniel Shipyards wants to develop control charts to assess the quality of its steel
plate. They take ten sheets of 1" steel plate and compute the number of cosmetic flaws on eac...
McDaniel Shipyards wants to develop control charts to assess the quality of its steel plate. They take ten sheets of 1" steel
plate and compute the number of cosmetic flaws on each roll. Each sheet is 20' by 100'. Based on the following data,
develop limits for the control chart, plot the control chart, and determine whether the process is in control. Answer the
following questions below.
Number of
flaws
Sheet
1
1
2
1
=
3
2
4
0
5
1
6
5
7
0
8
2
9
10
0
2
PLEASE WRTIE NEATLY AND EXPLAIN! (: Thanks
1. Calculate the standard deviation of control chart.
(a) the standard deviation = 1.0832
(b) the standard deviation = 1.1832
(c) the standard deviation = 1.4
(d) the standard deviation = 1.04 27.
2. Using +- 3 olimits, calculate the LCL and UCL for these data.
3.549; LCL = -3.549
(a) UCL
(b) UCL
3.549; LCL = 0 (
c) UCL
1.4; LCL = -1.4
(d) UCL
1.4; LCL = 0
(e) UCL
4.949; LCL = 0
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