Chapter 6, Problem 6.16QE

Interpretation Introduction

Interpretation:

The term diffusion and effusion terms have to be defined.

Concept Introduction:

The rate of diffusion of gases varies inversely to the square root of their mass densities given as follows:

  $\text{Rate of diffusion}=\frac{1}{\sqrt{\text{mass density}}}$

Graham’s law states that the rate of effusion of gases varies inversely to the square root of its molar mass. Mathematically it can be stated as follows:

  $\frac{{\text{Rate}}_{\text{1}}}{{\text{Rate}}_{\text{2}}}=\sqrt{\frac{{\left(\text{Molar}\text{Mass}\right)}_{\text{2}}}{{\left(\text{Molar Mass}\right)}_{\text{1}}}}$

Here,

${\left(\text{Molar}\text{Mass}\right)}_{\text{2}}$ denotes the molar mass of second gas.

${\left(\text{Molar Mass}\right)}_{\text{1}}$ denotes the molar mass of first gas.

${\text{Rate}}_{\text{1}}$ denotes rate of effusion of first gas.

${\text{Rate}}_{\text{2}}$ denotes rate of effusion of second gas.