Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 6, Problem 6.11QE
Interpretation Introduction
Interpretation:
The reason behind the deviation from ideal behavior for most of the gases at lower temperatures but not at higher temperatures has to be explained.
Concept Introduction:
In general, it has been found that gases obey the
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Draw the mechanism for the following Friedel-Craft reaction.
AlBr3
Br
(a) Draw the structures of A and B in the following reaction.
(i) NaNH2, NH3(1)
A
+
B
(ii) H3O+
For the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 →> NO₂+ NO3_(K1)
NO2 + NO3 → N2O5 (k-1)
NO2 + NO3 →
→
NO2 + O2 + NO (K2)
NO + N2O5-
NO2 + NO2 + NO2 (K3)
d[N₂O5] __2k‚k₂[N2O5]
Indicate whether the following rate expression is acceptable:
dt
k₁₁+ k₂
Chapter 6 Solutions
Chemistry: Principles and Practice
Ch. 6 - Prob. 6.1QECh. 6 - Prob. 6.2QECh. 6 - Prob. 6.3QECh. 6 - Prob. 6.4QECh. 6 - Prob. 6.5QECh. 6 - Prob. 6.6QECh. 6 - Prob. 6.7QECh. 6 - Prob. 6.8QECh. 6 - Prob. 6.9QECh. 6 - Prob. 6.10QE
Ch. 6 - Prob. 6.11QECh. 6 - Prob. 6.12QECh. 6 - Prob. 6.13QECh. 6 - Prob. 6.14QECh. 6 - Prob. 6.15QECh. 6 - Prob. 6.16QECh. 6 - Prob. 6.17QECh. 6 - Prob. 6.18QECh. 6 - Prob. 6.19QECh. 6 - Prob. 6.20QECh. 6 - Prob. 6.21QECh. 6 - Prob. 6.22QECh. 6 - Prob. 6.23QECh. 6 - Prob. 6.24QECh. 6 - A 39.6-mL sample of gas is trapped in a syringe...Ch. 6 - Prob. 6.26QECh. 6 - Prob. 6.27QECh. 6 - Prob. 6.28QECh. 6 - The pressure of a 900-mL sample of helium is...Ch. 6 - Prob. 6.30QECh. 6 - Prob. 6.31QECh. 6 - Prob. 6.33QECh. 6 - Prob. 6.34QECh. 6 - Prob. 6.35QECh. 6 - Prob. 6.36QECh. 6 - Prob. 6.37QECh. 6 - Prob. 6.38QECh. 6 - Prob. 6.39QECh. 6 - Prob. 6.40QECh. 6 - Prob. 6.41QECh. 6 - Prob. 6.42QECh. 6 - Prob. 6.43QECh. 6 - Prob. 6.44QECh. 6 - Prob. 6.45QECh. 6 - Prob. 6.46QECh. 6 - Prob. 6.47QECh. 6 - Prob. 6.48QECh. 6 - Prob. 6.49QECh. 6 - Calculate the molar mass of a gas if a 0.165-g...Ch. 6 - Prob. 6.51QECh. 6 - Prob. 6.52QECh. 6 - What is the density of He gas at 10.00 atm and 0...Ch. 6 - Prob. 6.54QECh. 6 - Prob. 6.55QECh. 6 - Prob. 6.56QECh. 6 - Prob. 6.57QECh. 6 - Prob. 6.58QECh. 6 - What volume, in milliliters, of hydrogen gas at...Ch. 6 - Prob. 6.60QECh. 6 - Heating potassium chlorate, KClO3, yields oxygen...Ch. 6 - Prob. 6.62QECh. 6 - Prob. 6.63QECh. 6 - Prob. 6.64QECh. 6 - Prob. 6.65QECh. 6 - Prob. 6.66QECh. 6 - Prob. 6.67QECh. 6 - Assuming the volumes of all gases in the reaction...Ch. 6 - Prob. 6.69QECh. 6 - Prob. 6.70QECh. 6 - Prob. 6.71QECh. 6 - Nitrogen monoxide gas reacts with oxygen gas to...Ch. 6 - Prob. 6.73QECh. 6 - Prob. 6.74QECh. 6 - Prob. 6.75QECh. 6 - Prob. 6.76QECh. 6 - Prob. 6.77QECh. 6 - Prob. 6.78QECh. 6 - Prob. 6.79QECh. 6 - Prob. 6.80QECh. 6 - Prob. 6.81QECh. 6 - What is the total pressure exerted by a mixture of...Ch. 6 - Prob. 6.83QECh. 6 - Prob. 6.84QECh. 6 - Prob. 6.85QECh. 6 - Prob. 6.86QECh. 6 - Prob. 6.87QECh. 6 - Prob. 6.88QECh. 6 - Prob. 6.89QECh. 6 - Prob. 6.90QECh. 6 - Prob. 6.91QECh. 6 - Prob. 6.92QECh. 6 - Prob. 6.93QECh. 6 - Prob. 6.94QECh. 6 - Prob. 6.95QECh. 6 - Prob. 6.96QECh. 6 - Prob. 6.97QECh. 6 - Prob. 6.98QECh. 6 - Prob. 6.99QECh. 6 - Prob. 6.100QECh. 6 - Prob. 6.101QECh. 6 - Prob. 6.102QECh. 6 - Prob. 6.103QECh. 6 - Prob. 6.104QECh. 6 - Prob. 6.105QECh. 6 - Prob. 6.106QECh. 6 - Prob. 6.107QECh. 6 - Prob. 6.108QECh. 6 - Prob. 6.109QECh. 6 - A gas effuses 1.55 times faster than propane...Ch. 6 - For each of the following pairs of gases at the...Ch. 6 - Prob. 6.112QECh. 6 - Prob. 6.113QECh. 6 - Prob. 6.114QECh. 6 - Calculate the pressure, in atm, of 10.2 mol argon...Ch. 6 - Prob. 6.116QECh. 6 - Prob. 6.117QECh. 6 - Prob. 6.118QECh. 6 - Prob. 6.119QECh. 6 - Workers at a research station in the Antarctic...Ch. 6 - Prob. 6.121QECh. 6 - A 1.26-g sample of a gas occupies a volume of 544...Ch. 6 - Prob. 6.123QECh. 6 - Calculate the mass of water produced in the...Ch. 6 - Prob. 6.126QECh. 6 - Prob. 6.127QECh. 6 - Prob. 6.128QECh. 6 - Prob. 6.129QECh. 6 - Prob. 6.130QECh. 6 - Prob. 6.131QECh. 6 - Prob. 6.132QECh. 6 - Prob. 6.133QECh. 6 - Prob. 6.134QECh. 6 - Prob. 6.135QECh. 6 - Prob. 6.136QE
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- Consider the following decomposition reaction of N2O5(g): For the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 → NO2 + NO3 (K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Indicate whether the following rate expression is acceptable: d[N2O5] = -k₁[N₂O₂] + K¸₁[NO₂][NO3] - K¸[NO₂]³ dtarrow_forwardIn a reaction of A + B to give C, another compound other than A, B or C may appear in the kinetic equation.arrow_forwardFor the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 →> NO₂+ NO3_(K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → → NO2 + O2 + NO (K2) NO + N2O5- NO2 + NO2 + NO2 (K3) d[N₂O5] __2k‚k₂[N2O5] Indicate whether the following rate expression is acceptable: dt k₁₁+ k₂arrow_forward
- Given the reaction R + Q → P, indicate the rate law with respect to R, with respect to P and with respect to P.arrow_forwardSteps and explanations. Also provide, if possible, ways to adress this kind of problems in general.arrow_forwardk₁ Given the reaction A B, indicate k-1 d[A] (A). the rate law with respect to A: (B). the rate law with respect to B: d[B] dt dtarrow_forward
- k₁ Given the reaction R₂ R + R, indicate k-1 (A). the rate law with respect to R2: (B). the rate law with respect to R: d[R₂] dt d[R] dtarrow_forwardGiven the reaction R+ Q → P, indicate (A). the rate law with respect to P: (B). the rate law with respect to R: (C). the rate law with respect to Q: d[P] dt d[R] dt d[Q] dtarrow_forwardThe reaction for obtaining NO2 from NO and O2 has the rate equation: v = k[NO]2[O2]. Indicate which of the following options is correct.(A). This rate equation is inconsistent with the reaction consisting of a single trimolecular step.(B). Since the overall order is 3, the reaction must necessarily have some trimolecular step in its mechanism.(C). A two-step mechanism: 1) NO + NO ⇄ N2O2 (fast); 2) N2O2 + O2 → NO2 + NO2 (slow).(D). The mechanism must necessarily consist of three unimolecular elementary steps with very similar rate constants.arrow_forward
- a. What is the eluent used in the column chromatography here (a “silica plug filtration” is essentially a very short column)? b. The spectroscopy of compound 5b is described in the second half of this excerpt, including 1H-NMR and 13C-NMR (which you will learn about in CHEM 2412L), MS (which you will learn about later in CHEM 2411L) and IR. One of the IR signals is at 3530 cm-1. What functional group does this indicate might be present in compound 5b?arrow_forwardSteps and explanations. Also provide, if possible, ways to adress this kind of problems in general.arrow_forwarda. The first three lines of this procedure describe the reaction used to make compound 5b. In the fourth line, hexane and sodium bicarbonate are added. What organic lab technique is being used here? b. What is the purpose of the Na2SO4? c. What equipment would you use to “concentrate [a solution] under reduced pressure”?arrow_forward
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