Titanium alloy with cylindrical structure has a modulus of elasticity of 107 GPa. The diameter of this alloy is 3.8 mm. It experiences only the deformation of elastic when the 2000 N tensile load is applied to it. The specimen is to be determined for maximum allowable elongation of 0.42 mm. Concept introduction: Concept of stress will be used which applied to the given specimen. The formula of stress is given as- σ = F A Here, F = force acting on the material A = area of material σ = stress applied to the material Concept of strain can be used to estimate the elongation in the alloy. The formula is given as- ε = Δ l l Here, e = strain Δl = change in length due to deformation l = initial length of material Concept of modulus of elasticity will be used. The formula elasticity modulus is given as- E = s t r e s s s t r a i n

Question

1. For the circuit shown, let Is = 10, R₁-45, R2-5, R3-5, and R4-45, to find: (choose the closest value in volts) (V) {NOTE: On Multiple Choice Questions, like this problem, you have only one attempt } • Vab 50 (V) -25 225 R₁ a R2 RA b R3 Vab

Answer 1

Question

Chapter 6, Problem 6.15P

Interpretation Introduction

Interpretation:

Titanium alloy with cylindrical structure has a modulus of elasticity of 107 GPa. The diameter of this alloy is 3.8 mm. It experiences only the deformation of elastic when the 2000 N tensile load is applied to it. The specimen is to be determined for maximum allowable elongation of 0.42 mm.

Concept introduction:

Concept of stress will be used which applied to the given specimen. The formula of stress is given as-

σ=FA

Here,

F = force acting on the material

A = area of material

σ = stress applied to the material

Concept of strain can be used to estimate the elongation in the alloy. The formula is given as-

ε=Δll

Here,

e = strain

Δl = change in length due to deformation

l = initial length of material

Concept of modulus of elasticity will be used. The formula elasticity modulus is given as-

E=stressstrain

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