Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
Question
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Chapter 6, Problem 25E

(a)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(a)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, NaBr(s)Na(aq)++Braq-

Explanation of Solution

NaBr(s)Na(aq)++Braq-

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  1

Figure 1

Let us consider the above molecular-level pictures of  NaBr(s) .  It should show equal

number of Na+ions and Br-ions .

(b)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(b)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is,. MgCl2(s) Mg(aq)2++2Cl(aq)-

Explanation of Solution

To draw the molecular-level pictures of  MgCl2(s) 

MgCl2(s) Mg(aq)2++2Cl(aq)-

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  2

Figure 2

Let us consider the above molecular-level pictures of  MgCl2(s)  should show twice the

number of 2Cl(aq)- ion as Mg(aq)2+ ions.

(c)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(c)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, Al(NO3)3(s)Al(aq)3++3NO3(aq)-

Explanation of Solution

To draw the molecular-level pictures of  Al(NO3)3(s)

Al(NO3)3(s)Al(aq)3++3NO3(aq)-

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  3

Figure 3

Let us consider the above molecular-level pictures of  Al(NO3)3(s) should show thrice the

number of 2Cl(aq)- ion as Mg(aq)2+ ions.

should show equal

number of 3NO3(aq)- ions as Al(aq)3+ ions.

(d)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(d)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is,  (NH4)2SO4(s)2NH4+(aq) + SO4(aq)2-

Explanation of Solution

To draw the molecular-level pictures of   (NH4)2SO4(s)

 (NH4)2SO4(s)2NH4+(aq) + SO4(aq)2-

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  4

Figure 4

Let us consider the above molecular-level pictures of   (NH4)2SO4(s)   should show

number of 2NH4+(aq) ions and one  SO4(aq)2- ion.

(e)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(e)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, NaOH(s) Na+(aq) + OH(aq)-

Explanation of Solution

To draw the molecular-level pictures of  NaOH(s)

NaOH(s) Na+(aq) + OH(aq)-

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  5

Figure 5

Let us consider the above molecular-level pictures of  NaOH(s)   should show equal

Number of Na+(aq) ions and Na+(aq) ion.

(f)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(f)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, FeSO4(s)Fe(aq)2++SO4(aq)2-

Explanation of Solution

To draw the molecular-level pictures of  FeSO4(s)

FeSO4(s)Fe(aq)2++SO4(aq)2-

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  6

Figure 6

Let us consider the above molecular-level pictures of  FeSO4(s)   should show equal

number of Fe(aq)2+ ions and one  SO4(aq)2- ion.

(g)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(g)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, KMnO4(s)K+(aq) + MnO4-(aq)

Explanation of Solution

To draw the molecular-level pictures of  KMnO4(s)

KMnO4(s)K+(aq) + MnO4-(aq) 

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  7

Figure 7

Let us consider the above molecular-level pictures of  KMnO4(s)   should show equal

number of K+(aq)  ions and one  MnO4-(aq)  ion

(h)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(h)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, HClO4(aq) H+(aq) + ClO4-(aq)

Explanation of Solution

To draw the molecular-level pictures of  HClO4(aq)

HClO4(aq) H+(aq) + ClO4-(aq)

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  8

Figure 8

Let us consider the above molecular-level pictures of  HClO4(aq)   should show equal

number of H+(aq) ions and one  ClO4-(aq) ion.

(i)

Interpretation Introduction

Interpretation:

Drawing the molecular-level pictures of strong electrolytes when its breaks up into component ions upon dissolving in water.

Concept Introduction:

Strong electrolyte totally dissociates in a solution.  These ions are good conductors of emotional current in the solution.

(i)

Expert Solution
Check Mark

Answer to Problem 25E

The dissociation of the given strong electrolyte is, NH4C2H3O2(s) NH4+(aq) + C2H3O2-(aq)

Explanation of Solution

To draw the molecular-level pictures of  NH4C2H3O2(s)

NH4C2H3O2(s) NH4+(aq) + C2H3O2-(aq)

Chemistry: An Atoms First Approach, Chapter 6, Problem 25E , additional homework tip  9

Figure 9

Let us consider the above molecular-level pictures of  NH4C2H3O2(s)   should show equal

Number of NH4+(aq) ions and one  C2H3O2-(aq) ion.

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Chapter 6 Solutions

Chemistry: An Atoms First Approach

Ch. 6 - Prob. 2ALQCh. 6 - You have a sugar solution (solution A) with...Ch. 6 - Prob. 4ALQCh. 6 - Prob. 5ALQCh. 6 - Prob. 6ALQCh. 6 - Consider separate aqueous solutions of HCl and...Ch. 6 - Prob. 8ALQCh. 6 - Prob. 9ALQCh. 6 - The exposed electrodes of a light bulb are placed...Ch. 6 - Differentiate between what happens when the...Ch. 6 - Consider the following electrostatic potential...Ch. 6 - Prob. 15QCh. 6 - A typical solution used in general chemistry...Ch. 6 - Prob. 17QCh. 6 - A student wants to prepare 1.00 L of a 1.00-M...Ch. 6 - List the formulas of three soluble bromide salts...Ch. 6 - When 1.0 mole of solid lead nitrate is added to...Ch. 6 - What is an acid and what is a base? An acid-base...Ch. 6 - A student had 1.00 L of a 1.00-M acid solution....Ch. 6 - Prob. 23QCh. 6 - Prob. 24QCh. 6 - Prob. 25ECh. 6 - Match each name below with the following...Ch. 6 - Prob. 27ECh. 6 - Commercial cold packs and hot packs are available...Ch. 6 - Calculate the molarity of each of these solutions....Ch. 6 - A solution of ethanol (C2H5OH) in water is...Ch. 6 - Calculate the concentration of all ions present in...Ch. 6 - Prob. 32ECh. 6 - Prob. 33ECh. 6 - Prob. 34ECh. 6 - Prob. 35ECh. 6 - Prob. 36ECh. 6 - Prob. 37ECh. 6 - Prob. 38ECh. 6 - A solution is prepared by dissolving 10.8 g...Ch. 6 - A solution was prepared by mixing 50.00 mL of...Ch. 6 - Calculate the sodium ion concentration when 70.0...Ch. 6 - Suppose 50.0 mL of 0.250 M CoCl2 solution is added...Ch. 6 - Prob. 43ECh. 6 - A stock solution containing Mn2+ ions was prepaned...Ch. 6 - On the basis of the general solubility rules given...Ch. 6 - On the basis of the general solubility rules given...Ch. 6 - When the following solutions are mixed together,...Ch. 6 - When the following solutions are mixed together,...Ch. 6 - For the reactions in Exercise 47, write the...Ch. 6 - For the reactions in Exercise 48, write the...Ch. 6 - Write the balanced formula and net ionic equation...Ch. 6 - Give an example how each of the following...Ch. 6 - Write net ionic equations for the reaction, if...Ch. 6 - Write net ionic equations for the reaction, if...Ch. 6 - Prob. 55ECh. 6 - Prob. 56ECh. 6 - What mass of Na2CrO4 is required to precipitate...Ch. 6 - What volume of 0.100 M Na3PO4 is required to...Ch. 6 - What mass of solid aluminum hydroxide can be...Ch. 6 - What mass of barium sulfate can be produced when...Ch. 6 - What mass of solid AgBr is produced when 100.0 mL...Ch. 6 - What mass of silver chloride can be prepared by...Ch. 6 - A 100.0-mL aliquot of 0.200 M aqueous potassium...Ch. 6 - A 1.42-g sample of a pure compound, with formula...Ch. 6 - You are given a 1.50-g mixture of sodium nitrate...Ch. 6 - Write the balanced formula, complete ionic, and...Ch. 6 - Write the balanced formula, complete ionic, and...Ch. 6 - Write the balanced formula equation for the...Ch. 6 - Prob. 70ECh. 6 - What volume of each of the following acids will...Ch. 6 - Prob. 72ECh. 6 - Hydrochloric acid (75.0 mL of 0.250 M) is added to...Ch. 6 - Prob. 74ECh. 6 - A 25.00-mL sample of hydrochloric acid solution...Ch. 6 - A 10.00-mL sample of vinegar, an aqueous solution...Ch. 6 - What volume of 0.0200 M calcium hydroxide is...Ch. 6 - A 30.0-mL sample of an unknown strong base is...Ch. 6 - A student titrates an unknown amount of potassium...Ch. 6 - The concentration of a certain sodium hydroxide...Ch. 6 - Assign oxidation states for all atoms in each of...Ch. 6 - Assign the oxidation state for nitrogen in each of...Ch. 6 - Prob. 84ECh. 6 - Specify which of the following are...Ch. 6 - Specify which of the following equations represent...Ch. 6 - Consider the reaction between sodium metal and...Ch. 6 - Consider the reaction between oxygen (O2) gas and...Ch. 6 - Balance each of the following oxidationreduction...Ch. 6 - Balance each of the following oxidationreduction...Ch. 6 - Prob. 91AECh. 6 - Prob. 92AECh. 6 - Prob. 93AECh. 6 - Prob. 94AECh. 6 - Prob. 95AECh. 6 - Consider a 1.50-g mixture of magnesium nitrate and...Ch. 6 - A 1.00-g sample of an alkaline earth metal...Ch. 6 - A mixture contains only NaCl and Al2(SO4)3. A...Ch. 6 - The thallium (present as Tl2SO4) in a 9.486-g...Ch. 6 - Prob. 100AECh. 6 - A student added 50.0 mL of an NaOH solution to...Ch. 6 - Prob. 102AECh. 6 - Acetylsalicylic acid is the active ingredient in...Ch. 6 - When hydrochloric acid reacts with magnesium...Ch. 6 - A 2.20-g sample of an unknown acid (empirical...Ch. 6 - Carminic acid, a naturally occurring red pigment...Ch. 6 - Chlorisondamine chloride (C14H20Cl6N2) is a drug...Ch. 6 - Prob. 108AECh. 6 - Prob. 109AECh. 6 - Many oxidationreduction reactions can be balanced...Ch. 6 - Prob. 111AECh. 6 - Calculate the concentration of all ions present...Ch. 6 - A solution is prepared by dissolving 0.6706 g...Ch. 6 - For the following chemical reactions, determine...Ch. 6 - What volume of 0.100 M NaOH is required to...Ch. 6 - Prob. 116CWPCh. 6 - A 450.0-mL sample of a 0.257-M solution of silver...Ch. 6 - The zinc in a 1.343-g sample of a foot powder was...Ch. 6 - Prob. 119CWPCh. 6 - When organic compounds containing sulfur are...Ch. 6 - Prob. 121CWPCh. 6 - Prob. 122CPCh. 6 - The units of parts per million (ppm) and parts per...Ch. 6 - Prob. 124CPCh. 6 - Prob. 125CPCh. 6 - Prob. 126CPCh. 6 - Consider the reaction of 19.0 g of zinc with...Ch. 6 - A mixture contains only sodium chloride and...Ch. 6 - Prob. 129CPCh. 6 - Prob. 130CPCh. 6 - Prob. 131CPCh. 6 - Consider reacting copper(II) sulfate with iron....Ch. 6 - Prob. 133CPCh. 6 - Prob. 134CPCh. 6 - What volume of 0.0521 M Ba(OH)2 is required to...Ch. 6 - A 10.00-mL sample of sulfuric acid from an...Ch. 6 - Prob. 137CPCh. 6 - A 6.50-g sample of a diprotic acid requires 137.5...Ch. 6 - Citric acid, which can be obtained from lemon...Ch. 6 - Prob. 140CPCh. 6 - Prob. 141CPCh. 6 - Tris(pentatluorophenyl)borane, commonly known by...Ch. 6 - In a 1-L beaker, 203 mL of 0.307 M ammonium...Ch. 6 - The vanadium in a sample of ore is converted to...Ch. 6 - The unknown acid H2X can be neutralized completely...Ch. 6 - Three students were asked to find the identity of...Ch. 6 - You have two 500.0-mL aqueous solutions. Solution...
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