The following reactions have to be balanced and completed. Concept introduction: A salt is produced when there is a complete neutralization of acid and base. The acid’s cation H + combines together with the base’s anion OH - to form water. The cation of the base forms the compound and the anion of the salt produces the salt.
The following reactions have to be balanced and completed. Concept introduction: A salt is produced when there is a complete neutralization of acid and base. The acid’s cation H + combines together with the base’s anion OH - to form water. The cation of the base forms the compound and the anion of the salt produces the salt.
Solution Summary: The author explains that the reaction is unbalanced since the number of Sodium atoms on reactant side and water on the product are not equal.
Interpretation: The following reactions have to be balanced and completed.
Concept introduction: A salt is produced when there is a complete neutralization of acid and base. The acid’s cation
H+ combines together with the base’s anion
OH- to form water. The cation of the base forms the compound and the anion of the salt produces the salt.
b)
Interpretation Introduction
Interpretation: The following reactions have to be balanced and completed.
Concept introduction: A salt is produced when there is a complete neutralization of acid and base. The acid’s cation
H+ combines together with the base’s anion
OH- to form water. The cation of the base forms the compound and the anion of the salt produces the salt.
c)
Interpretation Introduction
Interpretation: The following reactions have to be balanced and completed.
Concept introduction: A salt is produced when there is a complete neutralization of acid and base. The acid’s cation
H+ combines together with the base’s anion
OH- to form water. The cation of the base forms the compound and the anion of the salt produces the salt.
d)
Interpretation Introduction
Interpretation: The following reactions have to be balanced and completed.
Concept introduction: A salt is produced when there is a complete neutralization of acid and base. The acid’s cation
H+ combines together with the base’s anion
OH- to form water. The cation of the base forms the compound and the anion of the salt produces the salt.
Imagine an electrochemical cell based on these two half reactions with electrolyte concentrations as given below:
Oxidation: Pb(s) → Pb2+(aq, 0.10 M) + 2 e–
Reduction: MnO4–(aq, 1.50 M) + 4 H+(aq, 2.0 M) + 3 e– → MnO2(s) + 2 H2O(l)
Calculate Ecell (assuming temperature is standard 25 °C).
: ☐
+
Draw the Fischer projection of the most common naturally-occurring form of aspartate, with the acid group at the top and the side chain at the bottom.
Important: be sure your structure shows the molecule as it would exist at physiological pH.
Click and drag to start drawing a
structure.
✓
For a silver-silver chloride electrode, the following potentials are observed:
E°cell = 0.222 V and E(saturated KCl) = 0.197 V
Use this information to find the [Cl–] (technically it’s the activity of Cl– that’s relevant here, but we’ll just call it “concentration” for simplicity) in saturated KCl.
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