(a)
Interpretation: The correct statement has to be identified.
- a) A concentrated solution in water will always contain a strong or weak electrolyte.
- b) A strong electrolyte will breakup into ions when dissolved in water.
- c) An acid is strong electrolyte.
- d) All ionic compounds are strong electrolytes in water.
Concept introduction: A strong electrolyte generally conducts strong
b)
Interpretation: The correct statement has to be identified.
- a) A concentrated solution in water will always contain a strong or weak electrolyte.
- b) A strong electrolyte will breakup into ions when dissolved in water.
- c) An acid is strong electrolyte.
- d) All ionic compounds are strong electrolytes in water.
Concept introduction: A strong electrolyte generally conducts strong electric current and completely dissociates into separate ions. Whereas a weak electrolyte conducts electric current weakly and a small percentage of molecules are generally dissociated into ions.
c)
Interpretation: The correct statement has to be identified.
- a) A concentrated solution in water will always contain a strong or weak electrolyte.
- b) A strong electrolyte will breakup into ions when dissolved in water.
- c) An acid is strong electrolyte.
- d) All ionic compounds are strong electrolytes in water.
Concept introduction: A strong electrolyte generally conducts strong electric current and completely dissociates into separate ions. Whereas a weak electrolyte conducts electric current weakly and a small percentage of molecules are generally dissociated into ions.
d)
Interpretation: The correct statement has to be identified.
- a) A concentrated solution in water will always contain a strong or weak electrolyte.
- b) A strong electrolyte will breakup into ions when dissolved in water.
- c) An acid is strong electrolyte.
- d) All ionic compounds are strong electrolytes in water.
Concept introduction: A strong electrolyte generally conducts strong electric current and completely dissociates into separate ions. Whereas a weak electrolyte conducts electric current weakly and a small percentage of molecules are generally dissociated into ions.
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Chapter 6 Solutions
Chemistry: An Atoms First Approach
- The units of parts per million (ppm) and parts per billion (ppb) are commonly used by environmental chemists. In general, 1 ppm means 1 part of solute for every 106 parts of solution. Mathematically, by mass: ppm=gsolutegsolution=mgsolutekgsolution In the case of very dilute aqueous solutions, a concentration of 1.0 ppm is equal to 1.0 g of solute per 1.0 mL, which equals 1.0 g solution. Parts per billion is defined in a similar fashion. Calculate the molarity of each of the following aqueous solutions. a. 5.0 ppb Hg in H2O b. 1.0 ppb CHCl3 in H2O c. 10.0 ppm As in H2O d. 0.10 ppm DDT (C14H9Cl5) in H2Oarrow_forwardIf 4.12 L of a 0.850 MH3PO4 solution is be diluted to a volume of 10.00 L, what is the concentration of the resulting solution?arrow_forwardA student mixes four reagents together, thinking that the solutions will neutralize each other. The solutions mixed together are 50.0 mL of 0.100M hydrochloric acid, 100.0 mL of 0.200 M of nitric acid, 500.0 mL of 0.0100 M calcium hydroxide, and 200.0 mL of 0.100 M rubidium hydroxide. Did the acids and bases exactly neutralize each other? If not, calculate the concentration of excess H+ or OH ions left in solution.arrow_forward
- Complete and balance the equations for the following acid-base neutralization reactions. If water is used as a solvent, write the reactants and products as aqueous ions. In some cases, there may be more than one correct answer, depending on the amounts of reactants used. (a) Mg(OH)2(s)+HCl4(aq) (b) SO3(g)+H2O(l) (assume an excess of water and that the product dissolves) (c) SrO(s)+H2SO4(l)arrow_forwardWhat volume of 0.0105-M HBr solution is required to titrate 125 mL of a 0.0100-M Ca(OH)2 solution? Ca(OH)2(aq)+2HBr(aq)CaBr2(aq)+2H2O(l)arrow_forwardDescribe the use of gravimetric analysis to determine the percentage of chlorine in a water-soluble unknown solid.arrow_forward
- What is the difference between a solute and a solvent?arrow_forwardA common method for determining how much chloride ion is present in a sample is to precipitate the chloride from an aqueous solution of the sample with silver nitrate solution and then to weigh the silver chloride that results. The balanced net ionic reaction is :math>Ag+(aq)+Cl(aq)AgCl(s) ppose a 5.45-g sample of pure sodium chloride is dissolved in water and is then treated with a solution containing 1.15 g of silver nitrate. Will this quantity of silver nitrate be capable of precipitating all the chloride ion from the sodium chloride sample?arrow_forwardWhich of the following statements is/are true regarding solutions? l type='a'> If a solute is dissolved in water, then the resulting solution is considered aqueous. i>If two solutions are mixed and no chemical reaction occurs, then a net ionic equation cannot be written. i>If two clear solutions are mixed and then cloudiness results, this indicates that a precipitate formed.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
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