World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 6, Problem 19A

(a)

Interpretation Introduction

Interpretation: The molar mass of sodium nitride Na3N needs to be determined.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of any compound can be calculated with the help of atomic masses of component atoms.

(a)

Expert Solution
Check Mark

Answer to Problem 19A

Molar mass = 83.0 u

Explanation of Solution

Atomic mass of Na = 23.0 u

Atomic mass of N = 14.0 u

Molar mass of Na3N = ( 23.0× 3)+(14.0) = 83.0 u

(b)

Interpretation Introduction

Interpretation: The molar mass of carbon disulfide CS2 needs to be determined.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of any compound can be calculated with the help of atomic masses of component atoms.

(b)

Expert Solution
Check Mark

Answer to Problem 19A

Molar mass = 76.0 u

Explanation of Solution

Atomic mass of C = 12.0 u

Atomic mass of S = 32.0 u

Molar mass of CS2 = ( 12.0× 1)+(32.0×2) = 76.0 u

(c)

Interpretation Introduction

Interpretation: The molar mass of ammonium bromide NH4Br needs to be determined.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of any compound can be calculated with the help of atomic masses of component atoms.

(c)

Expert Solution
Check Mark

Answer to Problem 19A

Molar mass = 97.9 u

Explanation of Solution

Atomic mass of N = 14.0 u

Atomic mass of H = 1.001 u

Atomic mass of Br = 79.9 u

Molar mass of NH4Br = ( 14.0× 1)+(1.001×4)+(79.9×1) = 97.9 u

(d)

Interpretation Introduction

Interpretation: The molar mass of ethyl alcohol C2H5OH needs to be determined.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of any compound can be calculated with the help of atomic masses of component atoms.

(d)

Expert Solution
Check Mark

Answer to Problem 19A

Molar mass = 44.0 u

Explanation of Solution

Atomic mass of C = 12.0 u

Atomic mass of H = 1.001 u

Atomic mass of O = 16.0 u

Molar mass of C2H5OH = ( 12.0× 2)+(1.001×6)+(16.0×1) = 44.0 u

(e)

Interpretation Introduction

Interpretation: The molar mass of sulphurous acid H2SO3 needs to be determined.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of any compound can be calculated with the help of atomic masses of component atoms.

(e)

Expert Solution
Check Mark

Answer to Problem 19A

Molar mass = 66.0 u

Explanation of Solution

Atomic mass of S = 32.0 u

Atomic mass of H = 1.001 u

Atomic mass of O = 16.0 u

Molar mass of H2SO3 = ( 16.0× 1)+(1.001×2)+(16.0×3) = 66.0 u

(f)

Interpretation Introduction

Interpretation: The molar mass of sulphuric acid H2SO4 needs to be determined.

Concept Introduction: The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Mole concept is used to calculate the moles, mass, number of atoms and moles of a compound. The molar mass of any compound can be calculated with the help of atomic masses of component atoms.

(f)

Expert Solution
Check Mark

Answer to Problem 19A

Molar mass = 82.0 u

Explanation of Solution

Atomic mass of S = 32.0 u

Atomic mass of H = 1.001 u

Atomic mass of O = 16.0 u

Molar mass of H2SO4 = ( 16.0× 1)+(1.001×2)+(16.0×4) = 82.0 u

Chapter 6 Solutions

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Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY