Seven deletion mutations are tested for their ability to form wild-type recombinants with five point mutations as shown in the table below: Deletion mutation Point mutation 1 2 3 4 5 6 7 a - + - - + + - b + + + - + - - c + + + + - - - d - + + - + - - e + - - - + + - Using the data from the table, construct a genetic map of the order of point mutations and indicate the segment deleted by each deletion mutation. Introduction: The symbol ‘ + ’ indicates that a wild type recombination occurs and ‘ - ’ indicates that wild type recombinations are not formed. The result of insertion or deletion of a particular gene from the genome of an organism results in recombination. Point mutation is the one which only affects a single nucleotide in a particular gene of a genome. They include insertions or deletions of a single base pair. Point mutations are revertible i.e., wild type forms can be produced after reversion.

Question

There are five substitution mutations in the dark-colored mutant Mc1r gene. Compare the DNA sequence of the light-colored wild-type Mc1r gene with the DNA sequence of the dark-colored mutant Mc1r gene. Indicate the locations of the five mutations by changing the font color to YELLOW for the five single DNA nucleotidesthat are mutated in the mutant Mc1r gene table. Using the information in the introduction, determine whether each of these mutations is a silent, missense, or nonsense mutation. Using the mutant Mc1r gene data, fill in the columns (including DNA, mRNA, and amino acid) in gene table 2 that contain a silent mutation with BLUE. Likewise, fill in the columns that contain a missense mutation with RED. Shade any columns that contain nonsense mutations with GREEN.

Answer 1

Question

Chapter 6, Problem 14P

Summary Introduction

To analyze:

Seven deletion mutations are tested for their ability to form wild-type recombinants with five point mutations as shown in the table below:

Deletion mutation

Point mutation 1 2 3 4 5 6 7

a - + - - + + -

b + + + - + - -

c + + + + - - -

d - + + - + - -

e + - - - + + -

Using the data from the table, construct a genetic map of the order of point mutations and indicate the segment deleted by each deletion mutation.

Introduction:

The symbol ‘+’ indicates that a wild type recombination occurs and ‘-’ indicates that wild type recombinations are not formed. The result of insertion or deletion of a particular gene from the genome of an organism results in recombination. Point mutation is the one which only affects a single nucleotide in a particular gene of a genome. They include insertions or deletions of a single base pair. Point mutations are revertible i.e., wild type forms can be produced after reversion.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

There are five substitution mutations in the dark-colored mutant Mc1r gene. Compare the DNA sequence of the light-colored wild-type Mc1r gene with the DNA sequence of the dark-colored mutant Mc1r gene. Indicate the locations of the five mutations by changing the font color to YELLOW for the five single DNA nucleotidesthat are mutated in the mutant Mc1r gene table. Using the information in the introduction, determine whether each of these mutations is a silent, missense, or nonsense mutation. Using the mutant Mc1r gene data, fill in the columns (including DNA, mRNA, and amino acid) in gene table 2 that contain a silent mutation with BLUE. Likewise, fill in the columns that contain a missense mutation with RED. Shade any columns that contain nonsense mutations with GREEN.

In the table below, there are four versions of gene A, one of which is normal, and the other three which contain mutations that make the gene product nonfunctional. Focus on the shaded region of the sequence. Use the genetic code table to answer the question. How would you describe Mutation #2? Partial DNA sequence for gene A ("..." indicates many nucleotides of sequence not shown) 5' ... ATG GTG AGC AAG GAG GAG CTG TTC ACC TGT AAA TAG ... Normal Mutation #1 5' ... ATG GTG AGC AAG GAG AAG CTG TTC ACC TGT AAA TAG ... Mutation #2 5' ... ATG GTG AGC AAG TAG GAG CTG TTC ACC TGT AAA TAG ... Mutation #3 5' ... ATG GTG AGC AAG GAG CTG TTC ACC TGT AAA TAG ... Silent mutation Nonsense mutation Frameshift mutations Missense mútation

People with a commonly occurring, wild type allele of PTC with two adjacent thymines at a particular site in the coding sequence are more prone to BCCs than people without this allele. How can this be explained (one sentence)? The "two adjacent thymines" allele of PTC causes a bigger increase in BCC risk for people xeroderma pigmentosum (XP), who lacks components of the nucleotide excision repair pathway, compared to people without XP. How can this be explained (one sentence)?