Concept explainers
(a)
Graphing the equation.
(a)
Explanation of Solution
Given information:
Calculation:
Graph of
Graph of
Graph of
Graph of
Conclusion:
The graphs are the modulus function.
(b)
Graphs open up and down
(b)
Answer to Problem 1CB
Explanation of Solution
Given information:
Graphs of the function.
Calculation:
The graph of
Conclusion:
(c)
Effect of a in the direction of graph`s open.
(c)
Answer to Problem 1CB
As the sign of a negative so the the graph will open down and when a is positive so graph will open up.
Explanation of Solution
Given information:
Graph of given equation.
As the sign of a negative so the the graph will open down and when a is positive so graph will open up.
Conclusion:
As the sign of a negative so the the graph will open down and when a is positive so graph will open up.
(d)
To find:Slope of left and right of graph of each branch.
(d)
Answer to Problem 1CB
Slope of
Left branch is:-1 , Right branch is:1
Slope of
Left branch is:-1 , Right branch is:1
Slope of
Left branch is:2 , Right branch is:-2
Slope of
Left branch is:-2 ,Right branch is:2
Explanation of Solution
Given information:
Calculation:
Slope of
Left branch is:-1
Right branch is:1
Slope of
Left branch is:-1
Right branch is:1
Slope of
Left branch is:2
Right branch is:-2
Slope of
Left branch is:-2
Right branch is:2
Conclusion:
Slope of
Left branch is:-1 , Right branch is:1
Slope of
Left branch is:-1 , Right branch is:1
Slope of
Left branch is:2 , Right branch is:-2
Slope of
Left branch is:-2 ,Right branch is:2
(e)
To find:The relation between right slope and left slope.
(e)
Answer to Problem 1CB
The slope of left side is equal to slope of right side but the signs are opposite.
Explanation of Solution
Given information:
The slope of left side is equal to slope of right side but the signs are opposite.
Conclusion:
The slope of left side is equal to slope of right side but the signs are opposite.
Chapter 5 Solutions
EP ALGEBRA 1-ETEXT ACCESS
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