Chapter 5.6, Problem 2QCE

(a) ${\displaystyle {\int }_0^2\left(3x^2-2x\right)dx}=\text{\_\_\_\_\_\_}$

(b) ${\displaystyle {\int }_{-\pi }^{\pi }\cos xdx}=\_\_\_\_\_\_\_\_$

(c) ${\displaystyle {\int }_0^{\frac{1}{2}\ln 5}{e}^{x}dx}=\text{\_\_\_\_\_\_}$

(d) ${\displaystyle {\int }_{-1/2}^{1/2}\frac{1}{\sqrt{1-x^2}}dx}=\text{\_\_\_\_\_\_}$