Chapter 5.9, Problem 3ES

Express the integral in terms of the variable $u$ , but do not evaluate it.

(a) ${\displaystyle {\int }_0^1{e}^{2x-1}dx};u=2x-1$

(b) ${\displaystyle {\int }_e^{e^2}\frac{\ln x}{x}dx};u=\ln x$