Chapter 5.3, Problem 1AYU

$4^3=\text{ \_\_\_\_\_}$; $8^{2/3}=\text{ \_\_\_\_\_}$; $3^{-2}=\text{ \_\_\_\_\_}$. (pp. A8-A9 and pp, A89-A91)

To determine

To find: $4^3,8^{2/3}$ and $3^{-2}$

Answer to Problem 1AYU

64, 4 and $\frac{1}{9}$

Explanation of Solution

$4^3=4\times 4\times 4$

$=16\times 4$

$=64$

$8^{2/3}={\left(2^3\right)}^{2/3}$

$={\left(2\right)}^2$

$=4$

$3^{-2}=\frac{1}{3^2}=\frac{1}{9}$