Chapter 5.2, Problem 30SSC

To determine

The greatest horizontal force.

Answer to Problem 30SSC

Greatest horizontal force is equal to 168.56 N.

Explanation of Solution

Given:

Mass of table $m=40\text{ kg}$

Coefficient of static friction $\mu =0.43$

Formula used :

Greatest horizontal force is given by $F=\mu mg$ (1)

Here, $\mu$ is coefficient of static friction,m is mass and g is acceleration due to gravity.

Calculation:

Acceleration due to gravity is given by,

  $g=9.8{\text{ m/sec}}^2$

Now, putting the value of $\mu$ , m and g in equation (1).

  $\begin{array}{c}F=0.43\times 40\times 9.8\\ =168.56\text{ N}\end{array}$

Conclusion:

Therefore, greatest horizontal force will be equal to 168.56 N.