Chapter 5.2, Problem 28SSC

To determine

Magnitude of friction force.

Answer to Problem 28SSC

  $36.7\text{5 N}$

Explanation of Solution

Given:

Mass of table, $m=25\text{ kg}$

Coefficient of kinetic friction, ${\mu }_k=0.15$

Formula used:

  $F={\mu }_{k}mg$

Here, ${\mu }_k$ is coefficient of kinetic friction, m is mass and g is acceleration due to gravity.

Calculation:

Acceleration due to gravity is:

  $g=9.8{\text{ m/s}}^2$

Now, substitute the value of ${\mu }_k$ , m and g and solve:

  $\begin{array}{c}F=0.15\times 25\times 9.8\\ =36.75\text{ N}\end{array}$

Conclusion:a Therefore, frictional force is equal to $36.7\text{5 N}$ .