Chapter 5.1, Problem 12SSC

To determine

To Find: The component of vectors K and L.

Explanation of Solution

Given:

Vector K $=-4.0$

Vector L $=6.0$

Formula Used:

Horizontal and vertical components of a vector A can be obtained by:

  $\begin{array}{l}{A}_x=A\cos \theta \\ A_y=A\sin \theta \end{array}$

Calculation:

Components of vector K :

  $\begin{array}{l}{K}_x=-4.0\\ K_y=0\end{array}$

Components of vector L :

  $\begin{array}{l}{L}_x=6.0\\ L_y=0\end{array}$