Chapter 5, Problem 84E

a)

Interpretation Introduction

Interpretation:Order of average kinetic energy from low to high for $1.0\text{L}$ gas sample of ${\text{H}}_{\text{2}}$ , $\text{Xe}$ , ${\text{Cl}}_{\text{2}}$ , and ${\text{O}}_2$ should be determined.

Concept introduction:Expression of averagekinetic energy is as follows:

  ${\left(\text{KE}\right)}_{\text{avg}}=\frac{3}{2}RT$

Where,

• $R$ is gas constant.
• $T$ is temperature of gas.

b)

Interpretation Introduction

Interpretation: Order of average kinetic energy from low to high for $1.0\text{L}$ gas sample of ${\text{H}}_{\text{2}}$ , $\text{Xe}$ , ${\text{Cl}}_{\text{2}}$ , and ${\text{O}}_2$ should be determined.

Concept introduction:Expression of average kinetic energy is as follows:

  ${\left(\text{KE}\right)}_{\text{avg}}=\frac{3}{2}RT$

Where,

• $R$ is gas constant.
• $T$ is temperature of gas.

c)

Interpretation Introduction

Interpretation:Separation of $\text{1}\text{.0 L}$ gas of ${\text{O}}_2$ and ${\text{H}}_2$ that has same average velocityshould be explained.

Concept introduction:Expression of average kinetic energy is as follows:

  ${\left(\text{KE}\right)}_{\text{avg}}=\frac{3}{2}RT$

Where,

• $R$ is gas constant.
• $T$ is temperature of gas.