a.
Interpretation: The flow rate of air needs to be calculated which is necessary to deliver the required amount of oxygen.
Concept Introduction:The expression relating the pressure, P, volume, V with number of moles, n and temperature, T of an ideal gas is:
Where R is Universal gas constant.
a.
Answer to Problem 161CP
Explanation of Solution
Given:
The flow rate of methane in combustion chamber is 200. L/min at 1.50 atm and ambient temperature. At 1.00 atm and same temperature, the air is added to the chamber and gases are ignited.
The balanced chemical equation for the possible reaction is:
The molar amount of methane per minute is calculated using ideal gas equation as:
Substituting the values:
Now, according to balanced reaction, 1 mole of methane requires two moles of oxygen gas. So, if
The molar amount of air needed for per minute is calculated using mole fraction as:
Now, the volume required to deliver this amount of air per minute will be:
b.
Interpretation: The composition of the exhaust gas needs to be calculated in terms of mole fraction of
Concept Introduction:The mole fraction is ratio of number mole of a constituent present in the mixture to the total number of moles of all the constituents present in the mixture.
b.
Answer to Problem 161CP
Explanation of Solution
Given:
The combustion of methane is not complete under the conditions of part (a) and produces a mixture of
The complete balanced equations for the two possible process are:
The components present in the final mixture are:
Let the molar amount of methane be
The remaining amount of
The amount of
Now, by using the composition of air, the amount of
The total molar amount will be:
How, the mole fraction of each gas is calculated by dividing number of moles of each by total mole amount as:
c.
Interpretation: The partial pressure of each gas in the part (b) needs to be calculated when the total pressure of exhaust gas is 1.00 atm.
Concept Introduction:The formula used to calculate partial pressure is:
Where
c.
Answer to Problem 161CP
Explanation of Solution
The mole fraction of each gas as calculated in (b) part is:
The partial pressure of each gas is calculated using equation (a) as:
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Chapter 5 Solutions
Chemical Principles
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