Chapter 5, Problem 60A

Interpretation Introduction

Interpretation: The volume that water in the cylinder rise to be calculated.

Concept introduction: Amount of matter present in a substance in given volume is density. That is, density is ratio of mass of an object to its volume or mass per unit volume.

Answer to Problem 60A

New volume is 11.7mL.

Explanation of Solution

Expression for density is as follows:

  $\text{Density=}\frac{\text{Mass}}{\text{Volume}}$

Given, density of pure silver is $\text{10}\text{.5}\text{g}/{\text{cm}}^{\text{3}}$ and mass is 5.25 g. Put these values in density expression is as follows:

  $\begin{array}{c}\text{10}\text{.5}\text{g}/{\text{cm}}^{\text{3}}\text{=}\frac{\text{5}\text{.25g}}{\text{Volume}}\\ \text{Volume=}\frac{\text{5}\text{.25g}}{\text{10}\text{.5}\text{g}/{\text{cm}}^{\text{3}}}\\ \text{=0}{\text{.5cm}}^{\text{3}}\\ =0.5\text{mL}\end{array}$

After addition of pure silver to graduated cylinder the volume will be additive with 11.2mL. Thus new water level of cylinder is as follows:

  $\text{11}\text{.2mL+0}\text{.5mL=11}\text{.7mL}$

Conclusion

Mass of a substance per a given volume of that substance is density.