World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 5, Problem 37A
Interpretation Introduction

Interpretation: The conversion factor that is appropriate to express the cost of 5.3 lb of apples to be calculated.

Concept introduction: Scientific notation is quantitative information is called a measurement and exists of a number and a unit. By using scientific notation too large or too small numbers are conveniently expressed.

Expert Solution & Answer
Check Mark

Answer to Problem 37A

Cost of 5.3 lb of apples is 4.187$ .

Explanation of Solution

Significant figures are first uncertain number plus all certain numbers.

Given 1lb of apples = $0.79.

Conversion factor of this statement is as follows:

  1lb$0.79or$0.791lb

Second conversion factor is acceptable because it will cause quantity of pounds to be cancelled, allowing final cost to be quantified.

Conversion of 1849 to miles is as follows:

  5.3lb×$0.79lb=4.187$

Cost of 5.3 lb of apples is 4.187$ .

Conclusion

Inherent uncertainty of the measuring device determines number of significant figures for a given measurement.

Chapter 5 Solutions

World of Chemistry, 3rd edition

Ch. 5.2 - Prob. 6RQCh. 5.2 - Prob. 7RQCh. 5.3 - Prob. 1RQCh. 5.3 - Prob. 2RQCh. 5.3 - Prob. 3RQCh. 5.3 - Prob. 4RQCh. 5.3 - Prob. 5RQCh. 5.3 - Prob. 6RQCh. 5.3 - Prob. 7RQCh. 5 - Prob. 1ACh. 5 - Prob. 2ACh. 5 - Prob. 3ACh. 5 - Prob. 4ACh. 5 - Prob. 5ACh. 5 - Prob. 6ACh. 5 - Prob. 7ACh. 5 - Prob. 8ACh. 5 - Prob. 9ACh. 5 - Prob. 10ACh. 5 - Prob. 11ACh. 5 - Prob. 12ACh. 5 - Prob. 13ACh. 5 - Prob. 14ACh. 5 - Prob. 15ACh. 5 - Prob. 16ACh. 5 - Prob. 17ACh. 5 - Prob. 18ACh. 5 - Prob. 19ACh. 5 - Prob. 20ACh. 5 - Prob. 21ACh. 5 - Prob. 22ACh. 5 - Prob. 23ACh. 5 - Prob. 24ACh. 5 - Prob. 25ACh. 5 - Prob. 26ACh. 5 - Prob. 27ACh. 5 - Prob. 28ACh. 5 - Prob. 29ACh. 5 - Prob. 30ACh. 5 - Prob. 31ACh. 5 - Prob. 32ACh. 5 - Prob. 33ACh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - Prob. 59ACh. 5 - Prob. 60ACh. 5 - Prob. 61ACh. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 76ACh. 5 - Prob. 77ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STP
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